What is the area of the adjoining figure?

Option 2 is correct as area of given figure = area of rectangle + area of square = (l × b) + (l × l) = (50 × 21) + (25 × 25) = 1050 + 625 = 1675 m²

If in the given figure, the square has a side of 11 cm and each triangle has a height of 12 cm, then the area of the given figure is _______.

In each triangle, base = side of the square = 11 cm and the height = 12 cm (as given in the question) So, area of the given figure = area of square + 4 × area of a triangle = (l × l) + 4 × ((1/2) × b × h) = (11 × 11) + 4 × ((1/2) × 11 × 12) = 121 + 4 × (66) = 121 + 264 = 385 cm² So, option 4 is correct.

What is the perimeter of the adjoining figure?

Perimeter of given figure = (1/2) circumference of circle + 2 × length of rectangle + sum of 2 sides of triangle = [(1/2) × 2 ×(22/7) × r ] + (2 × 23) + ( 2 × 13) = [(1/2) × 2 × (22/7) × 7)] + (46) + (26) = 22 + 46 +26 = 94 m So, option 3 is correct.

Two equilateral triangles of side 9 cm are joined to each other as shown in the figure. What is the area of the complete figure?

Option 3 is correct as perimeter of given figure = sum of all sides = 6 × l = 6 × 9 = 54 cm

Supriya has a rectangular plot of length 62 m and breadth 54 m. She builds a square shaped house of side 49 m inside the rectangular plot and converts the remaining area into a garden. Area of the garden is equal to _______.

Option 2 is correct. Garden area = area of rectangular plot - area of square house = (l × b) - (l × l ) = (62 × 54) - (49 × 49 ) = 3348 - 2401 = 947 m²