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13 questions
A car driving from rest goes to the store 500 meters away and accelerates at 0.4 m/s^2. The car takes 18 seconds to get there. Eventually, the car reaches 7.2 m/s.
What was the car's time interval for the trip?
500 m
0.4 m/s^2
18 s
7.2 m/s
From a height of 16 meters, a frisbee is thrown forward with a velocity of 4 m/s to the right. What was the frisbee's initial velocity going down?
16 m
4 m/s
-9.8 m/s^2
0 m/s
A plane moving at 19 m/s lands on the runaway so that it can come to a rest. The plane accelerates at -0.6 m/s^2 over a displacement of 92 meters. What will the plane's final velocity be?
19 m/s
0 m/s
-0.6 m/s^2
92 meters
Starting at 2 m/s, a wheel accelerates at a rate of 4.2 m/s^2 for 7 seconds.
To find the Final Velocity, which equation should you use?
Vf = Vi + a*t
(Vf+Vi) / 2 * t = d
Vf ^2 = Vi ^2 + 2 * a * d
d = Vi * t + 0.5 * a * t^2
If a scuba diver swims down with a starting velocity of 0.2 m/s and ends at a velocity of 1.6 m/s. The scuba diver swam for 7 seconds. Which equation should be used to find the Displacement?
Vf = Vi + a*t
(Vf+Vi) / 2 * t = d
Vf ^2 = Vi ^2 + 2 * a * d
d = Vi * t + 0.5 * a * t^2
A car driving from rest goes to the store 500 meters away and accelerates at 0.4 m/s^2. The car takes 18 seconds to get there. Eventually, the car reached 7.2 m/s.
What was the car's Displacement for the trip?
500 m
0.4 m/s^2
18 s
7.2 m/s
Starting at 8.4 m/s, a wheel adds velocity at a rate of 1.7 m/s^2 for 9 seconds. What was the Acceleration of the wheel?
8.4 m/s
-9.8 m/s^2
1.7 m/s^2
9 s
A log rolls down a hill for 4 seconds and reaches the bottom after moving 200 meters. If the acceleration was at a rate of 3 m/s^2, what equation should be used to solve for the initial velocity going down?
Vf = Vi + a*t
(Vf+Vi) / 2 * t = d
Vf ^2 = Vi ^2 + 2 * a * d
d = Vi * t + 0.5 * a * t^2
A ball is thrown down a cliff with a starting velocity of 3.7 m/s and ends at a velocity of 42.9 m/s. The ball hits the ground after 4 seconds. What equation should be used to solve for Displacement
Vf = Vi + a*t
(Vf+Vi) / 2 * t = d
Vf ^2 = Vi ^2 + 2 * a * d
d = Vi * t + 0.5 * a * t^2
As an antelope bounds across the forest floor, it hears a predator in the bushes and accelerate away at a rate of 7.1 m/s^2. After hopping for 18 meters, the antelope reaches 20 m/s and manages to escape from being eaten. What equation should be used to solve for the Initial Velocity?
Vf = Vi + a*t
(Vf+Vi) / 2 * t = d
Vf ^2 = Vi ^2 + 2 * a * d
d = Vi * t + 0.5 * a * t^2
Starting at rest, a poodle starts to run to the North and accelerates for 5 seconds. The poodle ends with a velocity of 8.5 m/s to the North. Which of the following lists is correct?
Vi = 8.5 m/s N, t = 5 sec, Vf = 0 m/s
Vi = 0 m/s N, t = 5 sec, Vf = 8.5 m/s
Vi = 5 m/s N, t = 8.5 sec, Vf = 0 m/s
Vi = 8.5 m/s N, t = 0 sec, Vf = 5 m/s
A rain drop falls for 120 seconds from a cloud before reaching the ground. If the acceleration was at a rate of 9.8 m/s^2 and the initial velocity was 4 m/s, which of the following lists is Correct?
Vi = 4 m/s, t = 120 s, a = 9.8 m/s^2
Vi = 0 m/s, t = 120 s, a = -9.8 m/s^2
Vf = 120 m/s, t = 4 s, a = 0 m/s^2
Vi = 9.8 m/s, t = 120 s, a = 4 m/s^2
A humming bird has a starting velocity of 2.7 m/s and ends at a velocity of 8.7 m/s. iI the humming bird was flying for 49 meters, which of the following lists is correct?
Vi = 8.7 m/s, d = 49 m, Vf = 2.7 m/s
Vi = 0 m/s, d = 2.7 m, Vf = 49 m/s
Vi = 9.8 m/s, d = 49 m, Vf = 8.7 m/s
Vi = 2.7 m/s, d = 49 m, Vf = 8.7 m/s
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