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16 questions
What is the value of sin2x + 1+tan2x1
4
3
1
2
secx−1tanx+sec x +1 tanx=?
2 tan x
2 sec x
2 tan x sec x
2 cosec x
9sec2x − 9tan2x = ?
1
9
8
0
If 8 tan x = 15, then sin x – cos x is equal to
7/8
7/15
8/15
8/7
secx . cosx = ?
-1
1
0
2
tan x = 2/5, cos x = 5/2 then sin x ?
0
2
3
1
tan x = 7/10, sin x = 2/5 then sec x = ?
7/4
7/11
4/7
11/7
tan2x − sec2x = ?
1
0
2
-1
(1 + cot2x)cos2x = ?
tan2x
sin2x
cot2x
cos2x
(1 + tan2x)sin2x = ?
tan2x
sin2x
1
0
(1 + tan2x)cos2x = ?
0
sec2x
1
cos2x
If cos x = 5/4 then sin x ?
3/4
4/3
4/5
5/4
If sin x = 7/25, find the values of cos x and tan x.
cos x = 24/25 and tan x = 7/24
cos x = 16/25 and tan x = 11/24
cos x =9/25 and tan x =7/24
cos x = 24/25 and tan x = 2/11
Evaluate:2sin230tan60–3cos260sec230.
3 − 1
3
2−3
223
Given A= 60 and B = 30, Find Sin A Cos B + Cos A Sin B = ?
1
2
3
4
Find , if sin (x + 36) = cos x, where x+ 36 is an acute angle.
17
54
27
36
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