$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$ax^2+bx+c=0$

$y=a\left(x-h\right)^2+k$

$a^2+b^2=c^2$

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$ax^2+bx+c=0$

$y=a\left(x-h\right)^2+k$

$a^2+b^2=c^2$

{1, -6}

{3, 2}

{-3, 2}

{-1, 6}

{-1, 9}

{-9, 1}

(2, 18)

{2, 16}

$\left\{\frac{7}{2},\ -6\right\}$

$\left\{-\frac{5}{2},\ 5\right\}$

$\left\{\frac{-3}{7},\ 6\right\}$

$\left\{-\frac{5}{2},\ 7\right\}$