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- 1. Multiple Choice
What is the standard equation of a circle?
(x-k)2 + (y-h)2 = r2
(x+h)2 + (y+k)2 = r2
(x-h)2 + (y-k)2 = r2
(k-x)2 + (h-y)2 = r2
- 2. Multiple Choice
What does (h,k) stand for in the standard circle equation?
(h,k) is the center of the circle
(h,k) is a point on the circle.
(h,k) is a point that we guess and find
(h,k) is the distance of the circle
- 3. Multiple ChoiceIn the equation (x-3)2+(y+4)2=121, the radius of the circle is2421112122
- 4. Multiple ChoiceWhat is the equation of a circle with radius 2 and center (3, 4)?(x+3)2 + (y+4)2 = 2(x-3)2 + (y-4)2 = 2(x+3)2 + (y+4)2 = 4(x-3)2 + (y-4)2 = 4
- 5. Multiple Choice
What is the equation of the circle?(x+1)2 + (y +1)2 = 3(x+1)2 + (y -1)2 = 3(x+1)2 + (y +1)2 = 9(x-1)2 + (y -1)2 = 9 - 6. Multiple ChoiceWhat are the coordinates of the center and the radius of the circle with equation:
(x - 4)2 + (y - 3)2 = 25 ?Center (4,3)
Radius = 5 unitsCenter (4,3)
Radius = 25 unitsCenter (-4,-3)
Radius = 25 unitsCenter (-4,-3)
Radius = 5 units - 7. Multiple Choice
The diameter of a circle has length 12. The center is at (-5, 2). Give the equation of the circle.
(x + 5)2 + (y - 2)2 = 144
(x - 5)2 + (y + 2)2 = 36
(x + 5)2 + (y - 2)2 = 36
(x - 5)2 + (y + 2)2 = 12
- 8. Multiple Choice
The point (3,3) is on a circle whose center is at (-1,3). Write the standard form of the equation of the circle.
(x-3)2+(y-3)2=4
(x-3)2+(y-3)2=16
(x+1)2+(y-3)2=9
(x+1)2+(y-3)2=16
- 9. Multiple Choice
Write the equation of a circle with its diameter whose endpoints are (2,7) and (4,-3). Hint: first find the center of the circle using midpoint formula.
(x-3)2+(y-2)2=26
(x+3)2+(y+2)2=26
(x+1)2+(y-5)2=13
(x+1)2+(y-5)2=89
- 10. Multiple Choice
What is the equation of the circle.
(x - 3)2 + (y + 4)2 = 9
(x - 3)2 + (y + 4)2 = 3
x2 + y2 = 9
(x - 1)2 + (y + 1)2 = 7
- 11. Multiple Choice
What is the center of the circle with equation x2 + y2 = 1?
(1, 1)
(0, 0)
(0,1)
not enough information
- 12. Multiple Choice
(x - 1)2 + (y + 2)2 = 2
(x + 2)2 + y2 = 4
x2 + (y + 2)2 = 4
x2 + (y + 2)2 = 2
- 13. Multiple Choice
Write the equation of a circle with its diameter whose endpoints are (2,7) and (4,-3). Hint: first find the center of the circle using midpoint formula.
(x-3)2+(y-2)2=26
(x+3)2+(y+2)2=26
(x+1)2+(y-5)2=13
(x+1)2+(y-5)2=89
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