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15 questions
Write the equation of a circle with center (7, 0) with radius 3.
(x - 7)^{2} + y^{2} = 9
x^{2} + (y -7)^{2} = 9
(x - 7)^{2} + y^{2} = 3
x^{2} + (y -7)^{2} = 3
What are the coordinates of the center and the radius of the circle with equation:
(x - 4)^{2} + (y - 3)^{2} = 25 ?
Center (4,3)
Radius = 5 units
Center (4,3)
Radius = 25 units
Center (-4,-3)
Radius = 25 units
Center (-4,-3)
Radius = 5 units
What is the equation of the circle?
(x+1)^{2} + (y +1)^{2} = 3
(x+1)^{2} + (y -1)^{2} = 3
(x+1)^{2} + (y +1)^{2} = 9
(x-1)^{2} + (y -1)^{2} = 9
What is the center of the circle with this equation is (x+2)²+(y-4)²=41?
(-2,41)
(-2,4)
(2,-4)
(2,41)
What is the radius of the circle
(x+7)²+(y-2)²=144?
7
12
24
144
What is the equation for this circle?
(x+1)^{2}+(y+1)^{2}=9
x^{2}+y^{2}=9
x^{2}+y^{2}=6
x^{2}+y^{2}=3
What is the radius of the circle with this equation of (x-5)²+(y+7)²=8?
4
8
4√2
2√2
The diameter of a circle has length 12. The center is at (-5, 2). Give the equation of the circle.
(x - 2)^{2 }+ (y + 5)^{2 }= 36
(x - 5)^{2} + (y + 2)^{2} = 6
(x + 5)^{2 }+ (y - 2)^{2 }= 36
(x + 2)^{2 }+ (y - 5)^{2 }= 6
Find the center of the circle if the endpoints of a diameter of the circle are at (-12, -7) and (3, 5)
(-9/2, -1)
(-15/2, -6)
(9/2, 1)
(15/2, 6)
What is the standard equation of a circle?
(x-k)^{2} + (y-h)^{2} = r^{2}
(x+h)^{2} + (y+k)^{2} = r^{2}
(x-h)^{2} + (y-k)^{2} = r^{2}
(k-x)^{2} + (h-y)^{2} = r^{2}
What does (h,k) standard for in the standard circle equation?
(h,k) is the center of the circle
(h,k) is a point on the circle.
(h,k) is the radius of the circle
(h,k) is the diameter of the circle
In the circle represented by the equation (x-4)^{2}+(y-3)^{2}=25, the diameter is
10
3
5
25
In the equation (x+2)^{2}+(y-3)^{2}=4, the diameter of the circle is...
4
2
3
16
Which points lie on the circle represented by the equation (x+2)^{2 }+ (y+2)^{2} = 5^{2}
(-2, -2)
(6,4)
(8,8)
(-6, -5)
(-2, -7)
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