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The height of an object thrown into the air can be modeled by the formula y=−16x2+70x+95 , where y is in feet after x seconds.
What is the height of the object after 5 seconds?
95 feet
45 feet
70 feet
171.56 feet
The height of an object thrown into the air can be modeled by the formula y=−16x2+70x+95
, where y is in feet after x seconds.
What is the initial height of the object?
70 feet
95 feet
149 feet
-16 feet
A ball is thrown into the air with an upward velocity. Its height, h, after t seconds is given by the function below.
h=−16t2+64t+960
How many seconds did it take for the ball to reach its maximum height?
10 seconds
64 seconds
960 seconds
2 seconds
A ball is thrown into the air with an upward velocity. Its height, h, after t seconds is given by the function below.
h=−16t2+64t+960
What is the maximum height reached?
1024 feet
64 feet
960 feet
2 feet
h=−16t2+64t+960
A ball is thrown into the air with an upward velocity of 64 ft/s. Its height, h, after t seconds is given by the function above.
When did the ball hit the ground?
10 seconds
2 seconds
5 seconds
7 seconds
y=−16x2+88x
Henry launched a model rocket from the ground. Its height after x seconds can be modeled by the function above. When will the rocket be 40 feet high?
0.5 sec, 5 seconds
0.5 seconds
5 seconds
never
A dolphin jumps from the water at at initial velocity of 16 feet per second. The equation h = -16t2 + 80t models the dolphin's height at any given time, t. What is the maximum height the dolphin jumps?
1 foot
5 feet
96 feet
100 feet
Jason jumped off of a cliff into the ocean in Acapulco while vacationing with some friends. His height as a function of time could be modeled by the function h(t) = –16t2 + 16t + 480, where t is the time in seconds and h is the height in feet. How long does it take Jason to hit the water?
-16 seconds
-6 seconds
0 seconds
5 seconds
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