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- 1. Multiple Choice
What is the molar mass of NaCl?
58.45g/mol
28g/mol
12g/mol
6.02 x 1023
- 2. Multiple Choice
Calculate the % composition by mass of oxygen present in H2SO4.
16.3%
65.25%
32.6%
57.14%
- 3. Multiple ChoiceHow many moles are 98.3 grams of aluminum hydroxide, Al(OH)3?1.26 moles0.8 moles7,673.4 moles150 moles
- 4. Multiple ChoiceA compound consists of 72.2% magnesium(Mg) and 27.8% nitrogen(N) by mass. What is the empirical formula?Mg4N3MgN2Mg3N2MgN
- 5. Multiple Choice
Convert 25 g of NaBr to molecules
102.96 molecules
0.24 molecules
1.45x1023 molecules
2.34 x 1020molecules
- 6. Multiple Choice
What is the empirical formula for thr compound, CxHyOz , if the ratio C: H: O equal to 2: 2.5 : 1
C2H2O1
C2H5O1
C4H5O2
C3H2O2
- 7. Multiple Choice
The empirical formula for hydrocarbon A is C2H7O. If the molar mass of the hydrocarbon is 141 g/mol, determine the molecular formula for this hydrocarbon.
C2H7O
C4H14O2
C6H21O3
C8H28O4
- 8. Multiple Choice
Calculate the percentage of composition by mass of oxygen in Al(HCO3)3.
22.86 %
68.57 %
78.26 %
40.50 %
- 9. Multiple Choice
Given the following: 42.07% Na, 18.89% P, and 39.04% O, determine the empirical formula.
NaPO2
Na2PO3
Na3PO4
NaPO4
- 10. Multiple Choice
Which of the following statement are true about the formula of dinitrogen monoxide, N2O?
The relative molecular mass is 28.
One molecule of N2O consists of one nitrogen atom and one oxygen atom.
One mole of N2O contains 6.02 x 1023 atoms of nitrogen.
One mole of N2O consists of two mole of nitrogen atom and one mole of oxygen atom.
- 11. Multiple Choice
The mass of 4.50 x 1022 Cu atoms is ___________
4.75 g
63.55 amu
7.47 x 10-2 g
7.47 x 10-2 amu
- 12. Multiple Choice
Identify the number of Chlorine atoms in 65.8 g CaCl2.
7.14 x 1023 atoms
8.71 x 1023 atoms
1.22 x 1023 atoms
3.57 x 1023 atoms
- 13. Multiple Choice
Determine the number of moles of Na2CrO4 that contain 4.33 x 1024 oxygen atoms. Given the Avogadro’s number, NA is 6.02 x 1023.
7.19 mol
6.77 mol
1.80 mol
64.00 mol
- 14. Multiple Choice
What is the empirical formula if you have 81.82% carbon and 18.18% hydrogen?
C3H8
CH4
C2H2
C4H10
- 15. Multiple ChoiceHow many hydrogen atoms in 0.5 g ammonia?5.3144 x 1022 atoms1.7715 x 1022 atoms6.023 x 1022 atoms3.543 1022 atoms
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