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- 1. Multiple ChoiceChange the following equation to standard form
x2+y2-4x+12y-8=0(x+2)2+(y-6)2=48(x-2)2+(y+6)2=48(x-6)2+(y-2)2=48(x+2)2+(y-6)2=48 - 2. Multiple ChoiceChange the following equation to standard form
x2+y2-4x+12y-8=0(x+2)2+(y-6)2=48(x-2)2+(y+6)2=48(x-6)2+(y-2)2=48(x+2)2+(y-6)2=48 - 3. Multiple ChoiceWhat is the center for the circle with this equation x²+y²+4x+6y-36=0?(-2,5)(2,7)(-2,-7)
- 4. Multiple ChoiceWhat is the radius of the circle with this equation x²+y²-10x+8y-23=0?428
- 5. Multiple ChoiceFind the center and radius of the circle: x2+y2+14x-2=-1center= -7,2 radius= 3center= -7,1 radius= 7center= -4,1 radius= 5
- 6. Multiple ChoiceIn the equation (x-3)2+(y-2)2=16, the center of the circle is...(3,2)(-3, -2)(-2, -3)(2, 3)
- 7. Multiple ChoiceIn the equation (x+2)2+(y-3)2=4, the radius of the circle is...42316
- 8. Multiple ChoiceIn the equation (x+2)2+(y-3)2=4, the center of the circle is at...(-2, 3)(-3, 2)(2, -3)(3, -2)
- 9. Multiple ChoiceWrite the standard equation of the circle with the given center and radius; center (0,0) and radius: 3x2+y2=3x2+y2=6x2+y2=9
- 10. Multiple ChoiceWhat is the equation of a circle with radius 2 and center (3, 4)?(x+3)2 + (y+4)2 = 2(x-3)2 + (y-4)2 = 2(x+3)2 + (y+4)2 = 4(x-3)2 + (y-4)2 = 4
- 11. Multiple ChoiceThe diameter of a circle has length 12. The center is at (-5, 2). Give the equation of the circle.(x - 2)2 + (y + 5)2 = 36(x - 5)2 + (y + 2)2 = 6(x + 5)2 + (y - 2)2 = 36(x + 2)2 + (y - 5)2 = 6
- 12. Multiple ChoiceFind the equation of the circle with center (−8,3) and (2,−5) is on the circle?
Hint: you need to find the radius by plugging in values for four variables
x=
y=
h=
k=
in (x-h)2+(y-k)2=r2(x+8)2+(y−3)2=164.5.(x+3)2+(y−8)2=164.(x)2+(y)2=164.(x+8)2+(y−3)2=164. - Answer choicesTagsAnswer choicesTags