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- 1. Multiple ChoiceSolve the following for cos2θ:
sin2θ + cos2θ = 1cos2θ = 1 - sin2θcosθ = 1 + sin2θcosθ = 1 - sinθcos2θ = Adj/hyp - 2. Multiple ChoiceSolve the following for tan2θ:
1 + tan2θ = sec2θtan2θ = sec2θ + 1tan2θ = sec2θ - 1tanθ = secθ - 1tan2θ = opp/adj - 3. Multiple ChoiceRewrite tan(x) in terms of sin(x) and cos(x).tan(x) = cos(x)/sin(x)tan(x) = 1/cot(x)tan(x) = sin(x)/cos(x)tan(x) = opp/adj
- 4. Multiple Choice
Please select the correct solutioncsc2 xcot2 xsin2 xsec2 x - 5. Multiple ChoicePlease select the correct solution cos 2 x + sin 2 x=1csc 2 x + sec 2 xsin 2 x1 - sin 2 x
- 6. Multiple ChoicePlease select the correct solutioncsc xsec xcot xtan x
- 7. Multiple ChoiceSimplifysin²θcosθtanθ1- sin²θ
- 8. Multiple ChoiceWhat is csc(x) equivalent to?1/sin(x)1/tan(x)sin(x)1/cos(x)
- 9. Multiple Choicesin²θcosθtanθ1- sin²θ
- 10. Multiple Choice-1sin θcsc θ1
- Answer choicesTagsAnswer choicesTags