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(x −3)2+(y − 2)2 =16
the center of the circle is...
(3,2)
(-3, -2)
(-2, -3)
(2, 3)
In the equation
(x+2)2+(y-3)2= √4
the radius of the circle is...
4
2
8
16
What is the center and radius for the
circle with this equation
x² +y² + 4x + 6y −36 = 0?
(-4,-6), r = 36
(4, 6), 4 = 6
(2, 3), r = 49
(−2,−3) , r = 7
What is the equation for this circle?
(x + 1)+(y + 1) = 9
x² + y² = 9
x + y=9
x² + y² = 3
x² − y² = 9
What is the radius of the circle with
this equation of
(x−5)² + (y+7)² = 8?
4
8
4√2
2√2
What is the equation of this circle?
(x−1)² + (y−2)² = 16
(x+1)² + (y+2)² = 4
(x+1)² + (y+2)² = 16
(x−2)² + (y−1)² = 16
What is the radius of the circle with
this equation
x² + y² − 10x + 8y −23= 0?
4
16
8
64
√23
What is the equation for the circle, if it has diameter endpoints at (3,-4) and (5,−4)?
(x - 4)² + (y + 4)² = 1
(x +1)² + (y − 4)² = 16
(x − 1)² + (y − 4)² = 16
(x + 1)² + (y + 4)² = 16
Find the center if the endpoints
of the diameter are at
(-12, -7) and (3, 5).
(-4.5, -1)
(-7.5, -6)
(4.5, 1)
(7.5, 6)
Find the center and radius of the circle: x2+y2+14x-2y=-1
center= -7,2 radius= 3
center= -7,1 radius= 7
center= -4,1 radius= 5
The center of a circle (-5,6) with point (-1,3). Write the equation of the circle.
(x+5)2+(y-6)2=25
(x-5)2+(y-2)2=25
(x-8)2+(y-6)2=49
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