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- 1. Multiple Choice
8x2 + 6x - 20 =
(4x - 5)(2x - 1) - 16
8x2 + 6x - 20 =
(4x - 5)(2x + 4)
8x2 + 6x - 20 =
(4x - 5)(2x - 4)
8x2 + 6x - 20 =
(4x - 5)(2x - 4) - 40
- 2. Multiple Choice
3x3 + x2 + 2x - 5 = (3x + 4)(x2 + x + 1)
3x3 + x2 + 2x - 5 = (3x + 4)(x2 + x + 1) + 9x - 1
3x3 + x2 + 2x - 5 = (3x - 2)(x2 + x + 1)
3x3 + x2 + 2x - 5 = (3x - 2)(x2 + x + 1) + x - 3
- 3. Multiple Choice
2x3 - x + 1 = (2x - 2)(x2 + x + 1) - x + 3
2x3 - x + 1 = (2x - 2)(x2 + x + 1)
2x3 - x + 1 = (2x + 2)(x2 + x + 1) - x - 1
2x3 - x + 1 = (2x + 2)(x2 + x + 1)
- 4. Multiple Choice
3x2 - 2x + 1 = (x - 1)(3x2 + x + 2)
3x2 - 2x + 1 = (x - 1)(3x + 1) + 2
3x2 - 2x + 1 = (x - 1)(3x - 5) + 6
3x2 - 2x + 1 = (x - 1)(3x2 - 5x + 6)
- 5. Multiple Choice
Use the remainder theorem to find the value of p(c):
p(x) = 2x2 - 3x + 1, c = 4.
p(4) = 45
p(4) = -43
p(4) = 21
p(4) = -19
- 6. Multiple Choice
Use the remainder theorem to find the value of p(c):
p(x) = 3x3 + 4x + 32, c = -2.
p(-2) = 0 so
3x3 + 4x + 32 =
(x + 2)(3x2 - 6x + 16)
p(-2) = 0 so
3x3 + 4x + 32 =
(x - 2)(3x2 - 6x + 16)
p(-2) = 36
p(-2) = 52
- 7. Multiple Choice
Use the remainder theorem to find the value of p(c):
p(x) = 4x3 + 3x + 38, c = -2.
p(-2) = 0 so
4x3 + 3x + 38 =
(x + 2)(4x3 - 8x + 19)
p(-2) = 0 so
4x3 + 3x + 38 =
(x - 2)(4x3 - 8x + 19)
p(-2) = 48
p(-2) = 60
- 8. Multiple Choice
You are given a polynomial and one of its zeros.
Factor the polynomial and find all of the real zeros.
x3 - 6x2 - x + 6, c = -1
x3 - 6x2 - x + 6 =
(x + 1)2 (x - 6); zeros are x = -1, 6
x3 - 6x2 - x + 6 =
(x - 1)2 (x - 6); zeros are x = 1, 6
x3 - 6x2 - x + 6 =
(x + 1)(x - 1)(x - 6); zeros are x = -1, 1,-6
x3 - 6x2 - x + 6 =
(x + 1)(x - 1)(x - 6); zeros are x = -1, 1, 6
- 9. Multiple Choice
You are given a polynomial and one of its zeros.
Factor the polynomial and find all of the real zeros.
x3 - 6x2 + 11x - 6, c = 1
x3 - 6x2 + 11x - 6 =
(x + 1)2 (x - 6); zeros are x = -1, 6
x3 - 6x2 + 11x - 6 =
(x - 1)(x + 1)(x - 6); zeros are x = -1, 1, 6
x3 - 6x2 + 11x - 6 =
(x - 1)(x - 2)(x - 3); zeros are x = 1, 2,3
x3 - 6x2 + 11x - 6 =
(x + 1)(x - 2)(x - 3); zeros are x = -1, 2, 3
- 10. Multiple Choice
What could be the equation for this polynomial?
(x - 1) (x + 1)2
(x + 1) (x - 1)2
(x - 1)(x + 1)
x2 - 1
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