Calculate the pKa of lactic acid, given that when the concentration of free acid is 0.01 M and lactate is 0.087 M and the pH is 4.8.
2. Open Ended
30 seconds
1 pt
Calculate the pH of a mixture of 0.1 M acetic acid and 0.2 M sodium acetate. The pKa of acetic acid is 4.76.
3. Open Ended
30 seconds
1 pt
Calculate the ratio of the acetate and acetic acid required in a buffer of pH 5.3.
4. Open Ended
30 seconds
1 pt
What is the pH of the buffer containing: 0.5 M sodium acetate and 1.0 M acetic acid?
5. Open Ended
30 seconds
1 pt
What will the pH if you dilute 100 ml of 0.5 M NaOH to 1L with distilled water?
6. Open Ended
30 seconds
1 pt
What volume of Acetic acid (17.6 N) and what amount (g) of Sodium Acetate would you need to prepare 100 ml of 0.2 M buffer, pH 4.66 (pKa of Acetic acid = 4.76 and MW of Sodium Acetate = 136)
7. Open Ended
30 seconds
1 pt
What is the pH of a 10‑8 M HCl solution?
8. Open Ended
30 seconds
1 pt
Calculate the pH of a solution prepared by mixing 500 ml of 0.25 M Sodium Acetate with 250 ml 0.1 M HCl.
9. Open Ended
30 seconds
1 pt
A 0.2 L of 0.05 M solution of dibasic (Na2HPO4) phosphate buffer is mixed with 0.16 L of 0.05 M monobasic (NaH2PO4) phosphate buffer. Calculate pH of the buffer solution
10. Open Ended
30 seconds
1 pt
What are the concentrations of HOAc (Acetic acid) and OAc‑ (Acetate) in a 0.2 M Acetate buffer, pH 5.0? The pKa for HOAc = 4.76
11. Open Ended
30 seconds
1 pt
Prepare 3 L of 0.2 M Acetate buffer, pH 5.0 starting with Sodium Acetate (MW= 136) and 1 N Acetic Acid (pKa = 4.76). Calculate the amount of Sodium Acetate (g) and amount of Acetic acid (ml)
12. Open Ended
30 seconds
1 pt
What is the pH of a solution when 100 ml of 0.1 N NaOH is added to 150 ml of 0.2 M HOAc?
13. Open Ended
30 seconds
1 pt
Determine the pH of a solution prepared by mixing a 15 ml of 0.085 M NaOH and 135 ml of distilled water.
14. Open Ended
30 seconds
1 pt
Given that 0.1 M solutions of acetic acid and sodium acetate, describe the preparation of a 1 L of sodium acetate buffer, pH 5.4.
15. Open Ended
30 seconds
1 pt
Calculate the ionic strength of 0.15 M solution of Fe2(SO4)3.
16. Open Ended
30 seconds
1 pt
Calculate the pH and pOH of 0.2 M solution of NaOH. Click
17. Open Ended
30 seconds
1 pt
How many mls of 12 M Acetic acid must be added to 500 ml of 0.5 M Sodium Acetate to prepare a buffer of pH 4.76? (pKa of Acetic Acid is 4.76)
18. Open Ended
30 seconds
1 pt
The pH of acetic acid was adjusted with concentrated NaOH, at what pH would you find an equal amount of acetic acid and its conjugate base? The pKa for acetic acid is 4.76
19. Open Ended
30 seconds
1 pt
Assume you have a 150 ml of 0.1 M HCl solution. You took 100 ml from it and added 400 ml of distilled water into it. What will be the pH of this new HCl solution?
20. Open Ended
30 seconds
1 pt
A 500 ml buffer solution containing 0.2 M formic acid and 0.25 sodium formate is mixed with 100 ml of 0.05 M HCl. What will be the pH of this new solution?
21. Open Ended
30 seconds
1 pt
What statement(s) is true when acids and bases neutralize each other?
a) The amount of H+ and OH‐ is the same
b) Water is produced
c) Salt is produced
d) All of the above
22. Open Ended
30 seconds
1 pt
What is the name of pH indicator you will use today for colorimetric method?
23. Open Ended
30 seconds
1 pt
List three methods of pH estimation that you will perform in pH Lab?
24. Open Ended
30 seconds
1 pt
Which of the compound is made up of strong acid and weak base?
a) Sodium acetate
b) Ammonium chloride
c) Ammonium hydroxide
d) None of the above
25. Open Ended
30 seconds
1 pt
In Henderson‐Hasselbalch equation, [A‐] stands for:
26. Fill in the Blank
30 seconds
1 pt
A change of 1 pH unit represents a _______change in the hydrogen ion concentration.
27. Open Ended
30 seconds
1 pt
Buffer
28. Open Ended
30 seconds
1 pt
Good Buffer Qualities
29. Open Ended
30 seconds
1 pt
Buffer capacity:
30. Open Ended
30 seconds
1 pt
pH Meter
31. Open Ended
30 seconds
1 pt
pKa Acetic acid
32. Open Ended
30 seconds
1 pt
pKa of NH4OH
33. Open Ended
30 seconds
1 pt
Ionic strength can be calculated using the following formula: