$$\sin\frac{13\pi}{6}$$  

$$\operatorname{ctg}\frac{2\pi}{3}=$$  

$$tg\left(-\frac{2\pi}{3}\right)$$  

$$\cos\left(\pi+\alpha\right)$$  

$$\sin\left(\alpha-\frac{\pi}{2}\right)$$  

$$\frac{6\cos95\degree-4\sin185\degree}{\cos275\degree}$$  

$$\sin210\degree+\cos\left(-480\degree\right)-\sqrt[]{3}\operatorname{ctg}480\degree$$  

$$\cos\left(-\frac{2\pi}{3}\right)-0.5\sin\frac{11\pi}{6}-tg\frac{21\pi}{4}$$  

$$\frac{tg\left(2\pi-\alpha\right)\cos\left(\pi-\alpha\right)}{tg\left(1.5\pi-\alpha\right)\cos\left(1.5\pi-\alpha\right)}$$  

$$\frac{tg\left(180\degree-\alpha\right)\cos\left(180\degree-\alpha\right)tg\left(90\degree-\alpha\right)}{\sin\left(90\degree+\alpha\right)\operatorname{ctg}\left(90\degree-\alpha\right)tg\left(90\degree+\alpha\right)}$$  

$$\frac{\sin^2\left(x-3\pi\right)\cos^3\left(0.5\pi+x\right)}{tg\left(1.5\pi-x\right)\sin^3\left(2.5\pi-x\right)\cos^2\left(0.5\pi-x\right)}$$