Select the square root of 400.

 $Find\ 3^{2\ }+\ 4^2=$ 

 $Find\ 14^{2\ }-\ 7^2=$  

 $Find\ \sqrt{100}+\ \sqrt{81}=$  

 $Find\ \ 11^2\ -\sqrt{121}=$  

 $2^2\ \ \ \ \ \ \sqrt{100}\ \ \ \ \ \ 11\ \ \ \ \ \ 3^2$  

Write these in ascending order.

Square root of 225.