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15 questions
An airplane accelerates down a runway at 3.20 m/s2 for 32.8 s until is finally lifts off the ground. Determine the distance traveled before takeoff.
1720 m
52.48 m
85.28
1754
It was once recorded that a Jaguar left skid marks that were 290 m in length. Assuming that the Jaguar skidded to a stop with a constant acceleration of -3.90 m/s2, determine the speed of the Jaguar before it began to skid.
47.6 m
2262 m
.007 m
.084 m
no correct option available
describe the motion as it relates to velocity from 3-4 second mark?
velocity is increasing
velocity is decreasing
velocity is constant
not enough information is provided
describe the relationship from 11 seconds to 14 seconds in terms of velocity
the object slows and comes to a stop
the object slows at a constant rate through the 14 second mark
the object is accelerating
the object maintains constant velocity
describe the relationship from the interval 14 seconds to 18 seconds as it correlates to velocity?
the object is slowing down
the object is speeding up
the object is slowing down in the opposite direction
the car is speeding up in the opposite direction
Explain the relationship of the slope
represents velocity
represents acceleration
is velocity in the opposite direction
velocity as a constant rate
what does the slope represent in this graph
velocity
acceleration
the constant velocity
the changing acceleration
Kinematic equation can only be used when you have a constant ....
Position
Velocity
Acceleration
Time
An object starts from rest and accelerates uniformly over a time of 7.35 seconds for a distance of 400 m. Determine the acceleration of the object. Choose the appropriate equation.
v=vo+at
d=vot+1/2at2
v2=vo2+2ad
d=1/2(v+vo)t
An object accelerates from rest, with a constant acceleration of 8.4 m/s2 , what will its velocity be after 11s? (v= the change in velocity)(d=displacement)
a=v/t
d=vi(t)+1/2a(t2)
vf2=vi2+2ad
d=[(vi+vf)/2]t
It was once recorded that a Jaguar left skid marks that were 290 m in length. Assuming that the Jaguar skidded to a stop with a constant acceleration of -3.90 m/s2, determine the speed of the Jaguar before it began to skid. (d=the displacement) (v= the change in velocity)
a=v/t
vf2=vi2+2ad
d=0.5(vi+vf)t
d=vit+0.5at2
vf=vi+at
If an object (A) has greater velocity than object (B) going the same direction, how does this affect acceleration
A is accelerating more quickly than B
B is accelerating more quickly than A
A and B are accelerating equally
not enough information is provided
two airplanes are flying directly towards each other at the same speed If the first airplane is flying at a velocity v, what is the the velocity of the second airplane?
2 x v
1/2 x v
-v
none of these
v
a spaceship accelerates uniformly from a earth and accelerates uniformly from 65.0 m/s to 162.0 m/s in 10 s. How far does it travel? (d=the displacement) (v= the change in velocity)
a=v/t
vf2=vi2+2ad
d=0.5(vi+vf)t
d=vit+0.5at2
vf=vi+at
A bike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4 m. Determine the acceleration of the bike.
0.712 m/s2
.100 m/s2
121.21 m/s2
9.8 m/s2
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