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6 questions
A conducting bar of length L is sliding with a constant velocity V along two conducting rails in the presence of a uniform magnetic field directed into the page. According to Faraday’s law, the emf induced across the ends of the bar is due to
The resistance of the circuit
The change in magnetic field strength
The change in the enclosed area in the magnetic field
The change in the current
An emf will be induced if the loop is moving into the plane of the paper, with its plane perpendicular to the magnetic field.
True
False
Which of the following actions could make the bulb light up? (Choose 3)
Move the bar and rails parallel to the magnetic field
Move the bar to the right or to the left
Increase the magnitude of the magnetic field
Move the bar and rails perpendicular to the magnetic field
conducting rod slides on rails to the right with a velocity 𝑣, and a uniform, the constant magnetic field is directed out of the page as shown in the figure below. What happened to the velocity of the rod?
Remains constant
Increases
Decreases
A 0.300 m wire is moved parallel to a 0.600 T magnetic field at a speed of 2 m/s. what emf is induced across the ends of the wire?
0 V
1.5 V
0.36 V
3.6 V
A conducting rod is sliding on metal rails with velocity v. A magnetic field B is out of the paper, the separation of the rails is L, and the resistance of the circuit is R. In what direction in the diagram is the current flowing in the conducting bar?
Up
Down
Up then down
Down then up
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