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20 questions
tanθ =
cosθsinθ
sinθcosθ
cosθ1
cotθ
sin2θ + cos2θ = 1
Solve for cos2θ .
cot2θ+1
sec2θ−1
tanθ+1
1−sin2θ
tanθcosθ can be written in a single trigonometric identity as:
cosθ
sinθ
secθ
cotθ
cos2θ1−cos2θ can be written in a single trigonometric identity as:
cos2θ
sin2θ
sec2θ
tan2θ
cosθ cscθ can be written in a single trigonometric identity as:
cosθ
sinθ
secθ
cotθ
Simplify
cot2θ(1+tan2θ)
csc²θ
sec²θ
cscθ
1
Simplify
sinθ(cscθ−sinθ)
secθ
cos2θ
sin2θ
cos2θsin2θ
Simplify
tanxcscxcosx
cosx1
1
cotx
-1
Simplify (secθ−1)(secθ+1)
2secθ
cot2θ
tan2θ
sec2θ+1
Simplify
csc x(cosx+sinx)
csc x
tan x + 1
cot x
cot x + 1
Simplify tanx(cotx + cscx)
1 + secx
1 + cscx
secx−1
tan2x
tan2θ1−cos2θ can be simplified as
cot2θ
tan2θ
sin2θ
cos2θ
What happens when you multiply two reciprocal functions?
You get a pythagorean identity
It equals 1
You get a quotient identity
It equals 0
Which of the following would be a step to prove the following identity? cscx−secx=sinxcosxcosx−sinx
sinx1−cosx1
sinxcosx−sinx
cosxcosx−sinx
sinxcosx1
One step in proving the identity below would be:
sec2θsec2θ−sec2θ1
sec2θtan2θ
Both A and B
Neither A nor B
tanθtanθ+cotθ can be simplified as:
csc2θ
cot2θ
sin2θ
cos2θ
sinθcotθ secθ
0
1
sinθ
cosθ
Simplify (secθ−1)(secθ+1)
2secθ
cot²θ
tan²θ
sec²θ + 1
Simplify
csc x(cosx+sinx)
csc x
tan x + 1
cot x
cot x + 1
Rewrite tanx in terms of sinx and cosx
tanx=sinxcosx
tanx=cotx1
tanx=cosxsinx
tanx=adjacentopposite
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