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- 1. Multiple Choice
Which equation(s) match the hanger diagram?
x + x + x = 1 + 1 + 1 + 1 + 1 + 1
3x = 6
2x = 6
3x = 5
x + 3 = 6
- 2. Multiple Choice
Which equation(s) matches the hanger diagram?
2y + 3 = 11
3y + 2 = 11
y + y + 3 = 11
2y = 11
y + y + 1 + 1 + 1 = 11
- 3. Multiple Choice
If the blue tear drop = 3, what does the green heart and blue quadrilateral have to equal to make the hanger balanced and also equal to 16?
heart = 8 and quadrilateral = 16
heart = 2 and quadrilateral = 8
heart = 8 and quadrilateral = 2
heart = 16 and quadrilateral = 8
- 4. Multiple Choice
What can be crossed out on each side and still keep the mobile balanced?
1 trapezoid
2 circles
1 circle and 1 trapezoid
3 circles
- 5. Multiple Choice
Which equation represents the mobile with the trapezoid as the unknown?
20 = 2x + 8
5 = 2x + 2
16 = x + 8
20 = 2x + 4
- 6. Multiple Choice
What is the value of the trapezoid?
4
8
6
5
- 7. Multiple Choice
Which equation represents this mobile if the trapezoid is the unknown?
2x + 24 = x + 9
3x + 6 = 27
3x + 16 = 17
3x + 2 = 27
- 8. Multiple Choice
What is the value of the Trapezoid?
3
6
7
11
- 9. Multiple Choice
What moves can be made to keep the mobile balanced?
Take away 4 squares on both sides
Take away 2 circles on the left and 3 triangles on the right
Take away 2 circles and 2 squares from both sides
Take away 2 triangles on both sides
- 10. Multiple Choice
If the circle is 2 and each triangle is 1, which equation would help solve for the value of the square?
4x + 2 = 2x + 14
x + 6 = 2x + 10
4x + 2 = 2x + 8
4x + 6 = 2x + 10
- 11. Multiple Choice
If the circle is 2 and each triangle is 1, the mobile is represented by
4x + 6 = 2x + 10. What step could be made and still keep the mobile balanced?
subtract 6 from both sides
Add 10 to both sides
add 6 and 10 together
Add 6 to both sides
- 12. Multiple Choice
If the circle is 2 and each triangle is 1, the mobile is represented by
4x + 6 = 2x + 10. What is another step that could be made and still keep the mobile balanced?
Add 2x and 4x together
Add 10 to both sides
Subtract 2x from both sides
Add 6 to both sides
- 13. Multiple Choice
What move can be made to keep both sides balanced?
2x + 5 = 4x + 8
Subtract 5 from both sides
Add 5 to both sides
Add 5 and 8
Divide 2 from both sides
- 14. Multiple Choice
What move can be made to keep both sides balanced?
2x + 5 = 4x
Subtract 5 from both sides
Add 5 to both sides
Subtract 2x from both sides
Divide 2 from both sides
- 15. Multiple Choice
What step was made to get from
2x - 4 = x + 10 to
2x = x + 14 ?
subtract x from both sides
subtract 10 from both sides
add -4 and 10
add 4 to both sides
- 16. Multiple Choice
What step was made to get from
3x - 10 = x + 5 to
2x - 10 = 5 ?
Subtract an x from both sides
add 10 to both sides
add x to both sides
subtract 3x from both sides
- 17. Multiple Choice
Which equation requires you to subtract 3x from both sides?
4x + 1 = 2x - 3
5x - 6 = 3x + 5
-3x - 7 = 2x + 1
1/3x + 4 = 4x + 3
- 18. Multiple Choice
Which equation requires you to subtract 4 from both sides?
7x + 6 = 4x + 12
2x - 4 = 3x + 8
5x + 4 = x + 7
x - 9 = 15
- 19. Multiple Choice
Simplify the expression
6(x + 2) - 4
6x + 12
6x + 8
2x + 8
14x
- 20. Multiple Choice
Distribute & Evaluate. -2(n + 5) + 3n
n + 10
n - 10
5n + 5
5n - 5
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