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16 questions
What are the solutions to this quadratic?
±81
±9
±3
No real solution
Find the values for n.
-4, 2
-2, 4
-16
-4
Find the zeros of this quadratic. (Solutions)
Hint: Set each factor equal to zero, then solve.
b=4/5, b=3
b=4, b=-3
b=1/5, b=3
b=4/5, b=-3
Determine the values of
a, b, and c for
the quadratic equation:
4x2 – 8x = 3
a = 4, b = -8, c = 3
a = 4, b =-8, c =-3
a = 4, b = 8, c = 3
a = 4, b = 8, c = -3
Suzie solves the equation below:
x2 + 4x - 12 = 2
(x - 2)(x + 6) = 2,
by setting x -2 = 0 and x + 6 = 0.
Her solutions are x = 2 and x = -6.
Is Suzie correct? Why or why not?
Yes, she factored correctly and then used the zero product property
Yes, she factored correctly and then square rooted.
No, she did factor correctly, but she can't use the zero product property as shown. She needed to set equation equal to zero.
No, she didn't factor correctly so the rest of her work is wrong.
Solve the following for k.
9k2 = 225
4
4, -4
25, -25
-5, 5
What are the zeros? (solutions)
-4, 2
-2, 4
-16
-4
What are the solutions?
-2, 4
-8
±8
No real solution
SOLVE:
f(x)=x2−10x+2 if f(x)=0
x= 5+92, 5−92
x= 51+92, 51−92
x= 5+23, 5−23
x= 51+23, 51−23
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