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8 questions
Determine the vertex of the parabola y=5(x-2)2–7
(5, -7)
(-2, -7)
(2, -7)
(-7, -2)
What is the axis of symmetry of the function
y = (x + 5)2 - 12
x = 5
x = -5
x = -12
x = 12
The axis of symmetry for the quadratic function
f(x) = y=2(x-6)2 - 9 is wriiten as
x = -9
x = 9
x = -6
x = 6
Convert to vertex form. f(x) = 4x2 - 32x +2
y=4(x+4)2 - 62
y=4(x-4)2 - 62
y=4(x-8)2 - 62
y=4(x+8)2 - 62
Convert to vertex form. y = -2x2 + 24x + 5
y=-2(x+12)2 + 77
y=-2(x-12)2 + 77
y=-2(x-6)2 + 77
y=-2(x+6)2 + 77
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