$y-3=\pm2\left(x+2\right)$  

 $y-3=\pm\frac{1}{2}\left(x+2\right)$  

 $y=\pm\frac{1}{2}x$  

 $y=\pm2x$  

(0,-6)

(0,6)

(6,0)

(-6,0)

 $\left(1,\pm5\right)$  

 $\left(\pm5,0\right)$  

 $\left(\pm5,1\right)$  

 $\left(\pm5,-1\right)$  

 $\left(1,\pm3\right)$  

 $\left(\pm3,0\right)$  

 $\left(\pm4,1\right)$  

 $\left(\pm3,1\right)$  

-2

-1

3

a فوق ال x

a فوق ال y

+

-

صح

خطأ