$\left(x+3\right)^2\ +\ \left(y-4\right)^2\ =\ 12$  

 $\frac{\left(x-2\right)^2}{4}+\frac{\left(y-2\right)^2}{25}=\ 1$  

 $\left(x-6\right)^2\ +\frac{y^2}{16}=1$  

 $x\ =\ \left(y-2\right)^2\ -\ 5$  

 $\frac{x^2}{25}-\ \frac{\left(y+2\right)^2}{9}\ =\ 1$  

 $\left(x+2\right)^2\ +\ \left(y-7\right)^2=\ 4$  

 $\frac{\left(x+3\right)^2}{4}\ +\ \frac{\left(y+1\right)^2}{4}\ =\ 1$  

 $y\ =\ -2\left(x-5\right)^2\ -\ 3$  

 $x^2\ +\ \frac{\left(y+2\right)^2}{9}=\ 1$  

 $\frac{\left(x+3\right)^2}{4}+\frac{\left(y+4\right)^2}{9}=1$  

 $y\ =\ -\left(x-5\right)^2\ -\ 2$  

 $y^2\ -\ \frac{\left(x-2\right)^2}{16}=\ 1$  

 $-x^2\ +y\ -2x\ +\ 1\ =\ 0$  

 $y^2+x\ +\ 6y\ +\ 4\ =\ 0$  

 $9x^2\ -\ y^2\ -72x\ -\ 2y\ +\ 134\ =\ 0$  

 $2y^2\ -\ 4x^2\ -\ 16x\ +\ 2y\ -\ 31\ =\ 0$  

 $3x^2\ +\ 8y^2\ -32y\ -\ 88\ =\ 0$  

 $2x^2\ +\ y^{ }+\ 1\ =\ 0$  

 $20x^2\ -\ 8y^2\ -\ 20\ x\ -\ 195\ =\ 0$  

 $16x^2\ +\ 10y^2\ +\ 100x\ -\ 40y\ -\ 116\ =\ 0$  

 $x^2\ +\ y^2\ -\ 6x\ -\ 8y\ +\ 24\ =\ 0$  

 $4y^2\ -\ 16x^2\ +\ 24y\ -\ 32x\ +\ 64\ =\ 0$  

 $y\ \ -\ x^2\ -\ 2x\ +\ 1\ -\ 0$  

 $4x^2\ +\ 4y^2\ +\ 4x\ +\ 4y\ +\ 7\ =\ 0$  

 $6x^2\ -\ 4y^2\ +\ 12x\ -16y\ -\ 31\ =\ 0$  

 $25x^2\ +\ 9y^2\ -\ 200x\ +\ 175\ =\ 0$