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25 questions
Write the recursive formula of 13, 9, 5...
f(n) =f(n−1) − 4; f(1) = 13
f(n) =f(n−1) +3; f(1) = 13
f(n) =f(n−1) -5; f(1) = 13
f(n) =f(n−1) +4; f(1) = 4
Write the recursive formula for 6, 17, 28, 39, 50....
f(n) = f(n−1) + 11; f(1) = 6
f(n) =f(n−1) − 4; f(1) = 6
f(n) =f(n−1) + 9; f(1) = 6
f(n) =f(n−1) + 6; f(1) = 6
Given the recursive formula, find the first four terms:
f(n) = f(n −1) + 5
f(1) = −16
-16, -21, -26, -31
5, -11, -27, -43
-16, -80, -500, -200
-16, -11, -6, -1
Is the sequence geometric or arithmetic?
6, 12, 18, 24...
Arithmetic
Geometric
Neither
What is the explicit rule for the sequence:
11, 22, 33, 44..
f(n) = 11n +11
f(n) = 0 + 11n
f(n) = 11 + 2n
What is the explicit form for the following sequence
3, 13, 23, 33, 43...
f(n)= −7+10n
f(n)= 10 + 3n
f(n)= 3 +10n
f(n) = 7 + 10n
What is the explicit equations for this function?
f(n) = 5 +2n
f(n) = 5 − 2n
f(n) = 0 + 2n
f(n) = 5 + 2n
Given the sequence:
25, 21, 17, 13,...
Write the explicit equation that models the sequence.
f(n) = 29 + 4n
f(n) = 29 − 4n
f(n) = 25 − 4n
f(n) = 25 + 4n
Select the explicit rule that represents the sequence.
68 + 11n
68 − 11n
79 − 11n
79 + 11n
Select the explicit rule that represents the sequence.
1 + 5n
6 + 5n
5n + 6
1 + 6n
The next two terms of the sequence 12,17,22,27 are
28 and 33
29 and 34
32 and 37
30 and 35
What is the rule (explicit equation) for the nth term given
60, 55, 50, 45, ...
f(n) = 60 − 5n
f(n) = 65 − 5n
f(n) = 65 + 5n
f(n) = 60 + 5n
Find the explicit rule for the table.
f(n) = 11 + 11n
f(n) = 0 + 11n
f(n) = 1 + 11n
f(n) = 11 + 2n
Find the explicit rule for the table.
f(n) = 5 + 2n
f(n) = 3 + 2n
f(n) = 3 − 2n
f(n) = 5 − 2n
Which of the following equations is explicit?
f(n) = 5 + 4n
f(n) = f(n-1) x 5
2, 5, 8, 11, 14
What's the explicit equation?
f(n) = − 1+ 3n
f(n) = 2 + 3n
f(n) = f(n-1) + 3
f(n) = f(n+3) + 1
What is the recursive equation for this function?
f(1) = 3
f(n) = f(n-1) - 2
f(1) = 5
f(n) = f(n-1) + 2
f(1) = 5
f(n) = f(n-1) - 3
f(1) = 5
f(n) = f(n-1) + 3
What is the recursive equation for this function?
f(1) = 1
f(n) = f(n-1) - 2
f(1) = 1
f(n) = f(n-1) + 2
f(1) = -1
f(n) = f(n-1) + 2
f(1) = -1
f(n) = f(n-1) - 2
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