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- 1. Multiple Choice
If the mean of frequency distribution is 7.5 and summation of fixi =120+3k, summation of fi= 30 then k is

40

35

50

45

- 2. Multiple Choice
The mode and mean is given by 7 and 8 respectively. Then the median is

1/13

13/3

23/3

33

- 3. Multiple Choice
The mean of the data 4,10,5,9,12 is

8

10

9

15

- 4. Multiple Choice
The median of the data 13,15,16,17,19,20 is

30/2

31/2

33/2

35/2

- 5. Multiple Choice
If the sum of frequencies is 24 then the value of x in the observation x,5,6,1,2 will be

4

6

8

10

- 6. Multiple Choice
The mean of following distribution is

Xi : 11 14 17 20

fi : 3 6 8 7

15.6

17

14.8

16.4

- 7. Multiple Choice
CI: 0-10 10-20 20-30 30-40 40-50

f: 20 30 24 40 18

the sum of lower limits of the modal class and median class is

20

30

40

50

- 8. Multiple Choice
CI: 0-5 6-11 12-17 18-23 24-29

f: 26 20 30 16 22

The upper limit of the median class is

18.5

18

17.5

17

- 9. Multiple Choice
Mode and median of a data are 12k and 15k. Median of the data is

12k

14k

15k

16k

- 10. Multiple Choice
Mean of 100 items is 49. It was discovered that three times which should have been 60,70,80 were wrongly read as 40, 20, 50 respectively. The correct mean is

48

49

50

60

- 11. Multiple Choice
Marks: 0-10 10-20 20-30 30-40 40-50

No.of students: 3 9 13 10 5

The number of students who got marks less than 30 is

13

25

10

12

- 12. Multiple Choice
Mode is the

Middle most frequent value

Least frequent value

Max. Frequent value

None

- 13. Multiple Choice
If the mean of first n natural numbers is 5n/9 then n=?

6

7

9

10

- 14. Multiple Choice
If 35 is removed from the data 30, 34, 35,36,37,38,39,40 then the median increases by

2

1.5

1

0.5

- 15. Multiple Choice
The median when it is given that mode and mean are 8 and 9 respectively is

8.57

8.67

8.97

9.24

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