Have an account?
Skip to Content
Build your own quiz
Suggestions for you
15 questions
Show Answers
See Preview
- 1. Multiple Choice
If the mean of frequency distribution is 7.5 and summation of fixi =120+3k, summation of fi= 30 then k is
40
35
50
45
- 2. Multiple Choice
The mode and mean is given by 7 and 8 respectively. Then the median is
1/13
13/3
23/3
33
- 3. Multiple Choice
The mean of the data 4,10,5,9,12 is
8
10
9
15
- 4. Multiple Choice
The median of the data 13,15,16,17,19,20 is
30/2
31/2
33/2
35/2
- 5. Multiple Choice
If the sum of frequencies is 24 then the value of x in the observation x,5,6,1,2 will be
4
6
8
10
- 6. Multiple Choice
The mean of following distribution is
Xi : 11 14 17 20
fi : 3 6 8 7
15.6
17
14.8
16.4
- 7. Multiple Choice
CI: 0-10 10-20 20-30 30-40 40-50
f: 20 30 24 40 18
the sum of lower limits of the modal class and median class is
20
30
40
50
- 8. Multiple Choice
CI: 0-5 6-11 12-17 18-23 24-29
f: 26 20 30 16 22
The upper limit of the median class is
18.5
18
17.5
17
- 9. Multiple Choice
Mode and median of a data are 12k and 15k. Median of the data is
12k
14k
15k
16k
- 10. Multiple Choice
Mean of 100 items is 49. It was discovered that three times which should have been 60,70,80 were wrongly read as 40, 20, 50 respectively. The correct mean is
48
49
50
60
- 11. Multiple Choice
Marks: 0-10 10-20 20-30 30-40 40-50
No.of students: 3 9 13 10 5
The number of students who got marks less than 30 is
13
25
10
12
- 12. Multiple Choice
Mode is the
Middle most frequent value
Least frequent value
Max. Frequent value
None
- 13. Multiple Choice
If the mean of first n natural numbers is 5n/9 then n=?
6
7
9
10
- 14. Multiple Choice
If 35 is removed from the data 30, 34, 35,36,37,38,39,40 then the median increases by
2
1.5
1
0.5
- 15. Multiple Choice
The median when it is given that mode and mean are 8 and 9 respectively is
8.57
8.67
8.97
9.24
- Answer choicesTagsAnswer choicesTags