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13 questions
Two masses of mass 10.0 and 6.0 kg are hung from massless strings at the end of a light rod. The rod is virtually weightless. A pivot (fulcrum) is placed off center and the system is free to rotate. If the 6.0 kg mass is 4.0 m away from the pivot, how far away is the 10.0 kg mass if the system is not rotating?
0.42 m
2.4 m
4.8 m
4.2 m
Assuming the system is in equilibrium, calculate the missing distance d
3.4 m
2.8 m
4.4 m
1.6 m
The diagram shows a beam. Without any weights, the beam balances at its centre.
Three weights are hung as shown.
At which point does a load of 2 N balance the beam?
A
B
C
D
The figure below shows a man lifting a heavy rock using a steel bar. He pushes downwards on the end of the bar with a force F.
Which pivot positions allows the force F to be as small as possible?
A
B
C
D
A boy of weight 600N sits on the see-saw as shown at a distance of 1.5m from the pivot. What is the force F required at the other end to balance the see-saw?
450 N
350 N
4.5 N
200 N
What is the unit of moment f force?
N
m
Nm
N/m
Calculate the unknown force X!
4.0 N
6.0 N
10 N
12 N
At what distance should a 2N load placed from the pivot so that the see saw won't move?
0.2m
0.5m
0.45m
0.42m
State the principle of moments.
When a system is in equilibrium, the sum of the total clockwise moment is equal to the sum of the total anti-clockwise moment about the same pivot.
When a system is in equilibrium, the sum of the total clockwise moment is greater the sum of the total anti-clockwise moment about the same pivot.
When a system is in equilibrium, the sum of the total clockwise moment is less than the sum of the total anti-clockwise moment about the same pivot.
When a system is in equilibrium, the sum of the total clockwise moment is equal to the sum of the total anti-clockwise moment about the different pivot.
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