$\rightarrow$

$\vee$

$\wedge$

$\leftrightarrow$

 $\sim\left(p\vee q\right)$  

 $\sim\left(p\wedge q\right)$  

 $\sim\left(p\rightarrow q\right)$  

 $\sim p\rightarrow\sim q$  

If it is a quadrilateral, then a figure is a square.

If a figure is a square, then it is a quadrilateral.

If it is not a quadrilateral, then a figure is not a square.

If a figure is not a square, then it is not a quadrilateral.

The statement is formed by using the word "and".

The statement is false if both p and q are TRUE, otherwise it is FALSE.

The statement is true if both p and q are FALSE, otherwise it is FALSE.

The statement is true if both p and q are TRUE, otherwise it is FALSE.

 $p\rightarrow q\ is\ TRUE$  

 $p\rightarrow q\ is\ FALSE$  

 $\sim q\rightarrow p\ is\ FALSE$  

 $q\rightarrow p\ is\ FALSE$  

"q if and only if p"

"if p, then q"

“p if and only if q”

"if and only if p and q"

 $x=-3\ or\ 5x^2+1=46$  

 $x\ne-3\ or\ 5x^2+1\ne46$  

 $5x^2+1=46\ or\ x=-3$  

 $5x^2+1=46\ and\ x=-3$  

$\leftrightarrow$

$\vee$

$\wedge$

$\rightarrow$

 $\vee$  

 $\wedge$  

 $\sim$  

 $>$  

A circle hasn't a diameter of 14 cm.

A circle doesn't have a diameter of 14 cm.

A circle has no diameter of 14 cm.

A circle is not 14 cm.

Perpendicular lines intersect if and only if at a right angle.

Two lines are perpendicular if and only if they intersect at a right triangle.

Two lines are perpendicular if and only if they intersect at a right angle.

Two lines intersect at a right angle if and only if they are perpendicular lines.

or

and

not

if and only if

$\sim p\rightarrow\sim q$

$\sim q\rightarrow\sim p$

$q\rightarrow p$

$\sim\left(q\rightarrow p\right)$