Si

No

$\left(\sqrt{3}x^2+3x\right)\div\left(x+\sqrt{2}\right)$

$\left(x^2+\frac{3}{5}x-\frac{1}{3}\right)\div\left(\sqrt{x}+1\right)$

$\left(x^2-\frac{1}{3}\right)^{2\ }\div\left(x+\frac{4}{5}\sqrt{3}\right)$

$\left(\frac{1}{3}x\right)\div\left(\left(\sqrt{x}\right)^2-2\right)$

Cociente: $-2x-\frac{2}{3}$  y resto:  $\frac{19}{3}x-\frac{5}{6}$  

Cociente:  $2x+\frac{2}{3}$  y resto:  $\frac{19}{3}x-\frac{5}{6}$  

Cociente:  $-2x+\frac{2}{3}$  y resto:  $\frac{19}{3}x+\frac{11}{6}$  

Cociente:  $2x+\frac{2}{3}$   y resto:  $\frac{19}{3}x+\frac{11}{6}$