$\left(-1,\ 1\pm2\sqrt{5}\right)$  

 $\left(1,\ 1\pm2\sqrt{5}\right)$  

 $\left(1\pm2\sqrt{5},\ 1\right)$  

 $\left(1,\ 1\pm2\sqrt{5}\right)$  

 $\frac{\left(x-2\right)^2}{9}-\frac{\left(y-1\right)^2}{16}=1$  

 $\frac{\left(x-2\right)^2}{9}-\frac{\left(y+1\right)^2}{16}=1$  

 $\frac{\left(y-1\right)^2}{16}-\frac{\left(x-2\right)^2}{9}=1$  

 $\frac{\left(y+1\right)^2}{16}-\frac{\left(x-2\right)^2}{9}=1$  

 $\frac{\left(x-1\right)^2}{144}-\frac{\left(y+3\right)^2}{4}=1$  

 $\frac{\left(y-1\right)^2}{4}-\frac{\left(x-3\right)^2}{144}=1$  

 $\frac{\left(y+3\right)^2}{144}-\frac{\left(x-1\right)^2}{4}=1$  

 $\frac{\left(y+3\right)^2}{4}-\frac{\left(x-1\right)^2}{144}=1$  

 $\frac{\left(x+5\right)^2}{64}-\frac{\left(y+3\right)^2}{9}=1$  

 $\frac{\left(y+3\right)^2}{9}-\frac{\left(x+5\right)^2}{64}=1$  

 $\frac{\left(y+3\right)^2}{64}-\frac{\left(x+5\right)^2}{9}=1$  

 $\frac{\left(x+5\right)^2}{9}-\frac{\left(y+3\right)^2}{64}=1$  

 $\frac{\left(x+10\right)^2}{121}-\frac{\left(y+8\right)^2}{36}=1$  

 $\frac{\left(y+8\right)^2}{121}-\frac{\left(x+10\right)^2}{36}=1$  

 $\frac{\left(y+8\right)^2}{36}-\frac{\left(x+10\right)^2}{121}=1$  

 $\frac{\left(x+10\right)^2}{36}-\frac{\left(y+8\right)^2}{121}=1$