$\frac{\left(x-1\right)^2}{144}-\frac{\left(y+3\right)^2}{4}=1$  

 $\frac{\left(y-1\right)^2}{4}-\frac{\left(x-3\right)^2}{144}=1$  

 $\frac{\left(y+3\right)^2}{144}-\frac{\left(x-1\right)^2}{4}=1$  

 $\frac{\left(y+3\right)^2}{4}-\frac{\left(x-1\right)^2}{144}=1$  

 $\frac{\left(x+5\right)^2}{64}-\frac{\left(y+3\right)^2}{9}=1$  

 $\frac{\left(y+3\right)^2}{9}-\frac{\left(x+5\right)^2}{64}=1$  

 $\frac{\left(y+3\right)^2}{64}-\frac{\left(x+5\right)^2}{9}=1$  

 $\frac{\left(x+5\right)^2}{9}-\frac{\left(y+3\right)^2}{64}=1$  

 $\frac{\left(x+10\right)^2}{121}-\frac{\left(y+8\right)^2}{36}=1$  

 $\frac{\left(y+8\right)^2}{121}-\frac{\left(x+10\right)^2}{36}=1$  

 $\frac{\left(y+8\right)^2}{36}-\frac{\left(x+10\right)^2}{121}=1$  

 $\frac{\left(x+10\right)^2}{36}-\frac{\left(y+8\right)^2}{121}=1$