(0, ±√17)

(±√17, 0)

(0, ±√7)

(±√7, 0)

(0 , 5) ; (0 , -5)

(0 , 9) ; (0 , -9)

(5 , 0) ; (-5 , 0)

(9 , 0) ; (-9 , 0)

(-15 , 2) ; (9 , 2)

(15 , 2) ; (-9 , 2)

(-15 , -2) ; (9 , -2)

(15 , -2) ; (-9 , -2)

(-16 , 2) ; (10 , 2)

(-15 , 2) ; (9 , 2)

(-3 , 15) ; (-3 , -11)

(15 , -2) ; (-9 , -2)

 $\frac{\left(x+9\right)^2}{16}-\left(y-10\right)^2=1$  

 $\frac{\left(x+9\right)^2}{64}-\frac{\left(y-10\right)^2}{16}=1$  

 $\frac{\left(y-10\right)^2}{16}-\frac{\left(x+9\right)^2}{64}=1$  

 $\frac{\left(x+9\right)^2}{16}-\frac{\left(y-10\right)^2}{64}=1$  

 $\frac{\left(x-5\right)^2}{16}-\left(y-2\right)^2=1$  

 $\frac{\left(y-2\right)^2}{100}-\frac{\left(x-5\right)^2}{16}=1$  

 $\frac{\left(x-5\right)^2}{16}-\frac{\left(y-2\right)^2}{100}=1$  

 $\frac{\left(x-5\right)^2}{100}-\frac{\left(y-2\right)^2}{16}=1$  

$\frac{\left(x-2\right)^2}{16}-\frac{\left(y+3\right)^2}{20}=1$

$\frac{\left(x+3\right)^2}{16}-\frac{\left(y-2\right)^2}{20}=1$

$\frac{\left(x-2\right)^2}{20}-\frac{\left(y+3\right)^2}{16}=1$

$\frac{\left(y+3\right)^2}{16}-\frac{\left(x-2\right)^2}{20}=1$

$\frac{y^2}{25}-\frac{\left(x+2\right)^2}{1}=1$

$\frac{\left(x+2\right)^2}{25}-\frac{y^2}{1}=1$

$\frac{\left(x-2\right)^2}{1}-\frac{y^2}{25}=1$

$\frac{y^2}{25}+\frac{\left(x+2\right)^2}{1}=1$

$\frac{x^2}{25}+\frac{y^2}{11}=1$

$\frac{x^2}{5}-\frac{y^2}{11}=1$

$\frac{x^2}{11}-\frac{y^2}{25}=1$

$\frac{x^2}{25}-\frac{y^2}{11}=1$