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14 questions
What is the center of this hyperbola?
Center (−1, 4)
Center (1, 4)
Center (−1, −4)
Center (1, −4)
What are the foci of the hyperbola with the equation 12y2−5x2=1 .
(0, ±√17)
(±√17, 0)
(0, ±√7)
(±√7, 0)
What are the coordinates of the foci ?
(0 , √106) ; (0 , -√106)
(√106 , 0) ; (-√106 , 0)
(0 , √31) ; (0 , -√31)
(√31 , 0) ; (-√31 , 0)
What are the coordinates of the vertices?
(0 , 5) ; (0 , -5)
(0 , 9) ; (0 , -9)
(5 , 0) ; (-5 , 0)
(9 , 0) ; (-9 , 0)
What are the coordinates of the vertices ?
(-15 , 2) ; (9 , 2)
(15 , 2) ; (-9 , 2)
(-15 , -2) ; (9 , -2)
(15 , -2) ; (-9 , -2)
What are the coordinates of the foci ?
(-16 , 2) ; (10 , 2)
(-15 , 2) ; (9 , 2)
(-3 , 15) ; (-3 , -11)
(15 , -2) ; (-9 , -2)
Find the standard form of the hyperbola given
4x2−y2+72x+20y+160=0 .
16(x+9)2−(y−10)2=1
64(x+9)2−16(y−10)2=1
16(y−10)2−64(x+9)2=1
16(x+9)2−64(y−10)2=1
Find the standard form of the Hyperbola given that
25x2−4y2−250x+16y+209=0 .
16(x−5)2−(y−2)2=1
100(y−2)2−16(x−5)2=1
16(x−5)2−100(y−2)2=1
100(x−5)2−16(y−2)2=1
Find the equation of hyperbola.
16(x−2)2−20(y+3)2=1
16(x+3)2−20(y−2)2=1
20(x−2)2−16(y+3)2=1
16(y+3)2−20(x−2)2=1
Find the equation of the hyperbola.
25y2−1(x+2)2=1
25(x+2)2−1y2=1
1(x−2)2−25y2=1
25y2+1(x+2)2=1
A hyperbola has vertices (±5, 0) and one focus at (6, 0). What is the equation of the hyperbola in standard form?
25x2+11y2=1
5x2−11y2=1
11x2−25y2=1
25x2−11y2=1
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