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2. Solve the differential equation
𝑑𝑦/𝑑𝑡 =3𝑡2/𝑦 with initial condition
𝑦(2) = 0.
y=ln∣15t∣
y=16t3
y = 2t3−16
y=2t3−16
Determine the value of "c" that satisfies the differential equation dxdy=y+2x+1 if the curve goes through the point (0, -1).
5/2
-3/2
-1/2
1
Which of the following is the solution to the differential equation dxdy=yx2 with the initial condition y(3) = -2?
y=−2e(−9+3x3)
y=32x3
y=32x3−14
y=−32x3−14
Given the differential equation dP/Dt=5P
A) Find the general solution for P to the differential equation
B)Find the particular solution for P to the differential equation given P(0)= 418
A) P=Ce5t
B) P= 5e418t
A) P=Ce5t
B) P= 418e5t
A) P=Cet
B) P= 418et
A) P=Ce10t
B) P= 418e10t
Solve the following differential equations:
dxdy=cosy1
siny=1+C
siny=x+C
−siny=2x2+C
siny=0+C
Solve the following differential equations:
dxdy=ex
1=ex+C
y=2ex+C
y=ex+C
0=ex+C
Let dxdy=−0.4y and y=5 when x=0 .
What is the solution for y ?
y=5e−0.4x
y=−0.4e5x
y=5e−0.4x
y=0.4e5x
Solve the differential equation dtdy=y3t2 with initial condition 𝑦(2) = 0.
𝑦 = ln(15t)
𝑦 = 16t3
𝑦 = (2𝑡3 − 16)1/2
𝑦 = (2𝑡3 −16)
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