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16 questions
What is the "formula" for finding the axis of symmetry?
y=ax2+bx+c
x=2a−b
y=mx+b
x=2a−b±b2−4ac
Find the axis of symmetry for y=x2−8x+15
x = -4
x = 4
y = 4
y = -4
Find the vertex for y=x2−8x+15
(-4, 63)
(-4, 31)
(4, -1)
(4, -31)
Find the axis of symmetry of
y=3x2−6x+4
x=1
x=−6
x=2
x=−1
Find the vertex of y=3x2−6x+4
(1, 1)
(1, 7)
(2, 4)
(−2, 28)
Find the axis of symmetry for y=−x2−4x+12
x=−4
x=−2
x=4
x=2
Find the vertex of y=−x2−4x+12
(-2, 16)
(2, 0)
(2, 4)
(-2, 4)
Find the axis of symmetry of y=−2x2−16x+3
x=4
x=8
x=−4
x=−8
Find the vertex of y=−2x2−16x+3
(4, -93)
(-4, 35)
(-4,99)
(8,3)
Find the axis of symmetry of y=x2+16x+71
x=8
x=−8
x=16
x=−16
Find the vertex y=x2+16x+71
V(-8, 7)
V(-8, 3)
V(8, 10)
V(16, -2)
Find the axis of symmetry of
y=x2−2x−5
x=2
x=−2
x=1
x=−1
Find the vertex y=x2−2x−5
V(-2, 10)
V(-1, 15)
V(1, -6)
V(1, -12)
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