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This formula is used to find the amount of heat (energy) neccesary when there's a phase change
Q= (h)(ΔT)
Q=(m)(L)
Q=(m)(c)(ΔT)
Q=(k)(A)(dT)
the symbol for specific latent heat is
c
L
Q
m
How much heat must be lost to change of 110 grams of water at 0 ºC to 110 grams of ice at 0ºC? Heat of fusion = 334 kJ/kg; Specific heat of water = 4186 J/kgoC
Q = 110 x 4186
Q = 110000 x 4186
Q = 0.110 x 334
Q = 110 x 334
If the specific heat of water is 4,186 J/kg°C, how much heat is required to increase the temperature of 1.2 kg of water from 23 °C to 39 °C?
Q = 1.2 x 4186
Q = 1.2 x 4186 x 7
Q = 1.2 x 4186 x 17
Q = 0.0012 x 4186 x 17
There are four main processes in changing of phase, and they are
Melting
Boiling
Condensation
All the above
The heat absorbed by melting a solid is known as
latent heat of fusion
latent heat of solid
latent heat of liquid
latent heat of vaporisation
The graph shows the cooling curve of a substance. At which stages the specific latent heat released?
AB and CD
BC and DE
AB and EF
BC and CD
Consider the following temperature-time graph when a solid is heated. which part of the graph involves latent heat of vaporization?
Part I
Part II
Part III
Part IV
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