Latihan Identitas Trigonometri
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10 QuestionsShow answers
  • Question 1
    180 seconds
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    Q.

     Bentuk sederhana dari   sec2xtan2xcosec x\frac{\sec^2x-\tan^2x}{\operatorname{cosec}\ x}  adalah ...

    answer choices

     sin x\sin\ x  

     cos x\cos\ x  

     tan x\tan\ x  

     sec x\sec\ x  

     cosec x\operatorname{cosec}\ x  

  • Question 2
    180 seconds
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    Q.

    Identitas trigonometri yang benar adaalah...

    answer choices

    sin2x=1+cos2x\sin^2x=1+\cos^2x

    tan2x=1+sec2x\tan^2x=1+\sec^2x

    cotan2x=1+cosec2x\operatorname{cotan}^2x=1+\operatorname{cosec}^2x

    1=sec2xtan2x1=\sec^2x-\tan^2x

    1=cotan2xcosec2x1=\operatorname{cotan}^2x-\operatorname{cosec}^2x

  • Question 3
    300 seconds
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    Q.

     sin x1cos x+sin x1+cos x=\frac{\sin\ x}{1-\cos\ x}+\frac{\sin\ x}{1+\cos\ x}=  

    answer choices

     sin x\sin\ x  

     2 sin x2\ \sin\ x  

     2 cos x2\ \cos\ x  

     2sin x\frac{2}{\sin\ x}  

     2sin x\frac{-2}{\sin\ x}  

  • Question 4
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    Q.

     cotx +tan x\cot x\ +\tan\ x 



    answer choices

     secx cosecx\sec x\ \operatorname{cosec}x  

     tanx sinx\tan x\ \sin x  

     1tanx1-\tan x  

     1cosecx1-\operatorname{cosec}x  

     sec2x\sec^2x  

  • Question 5
    300 seconds
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    Q.

     (secx+tanx)(1sinx)=\left(\sec x+\tan x\right)\left(1-\sin x\right)=  

    answer choices

     sin x\sin\ x  

     cosx\cos x  

     tanx\tan x  

     secx\sec x  

     cotanx\operatorname{cotan}x  

  • Question 6
    300 seconds
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    Q.

     (1sin2x)(1+tan2x)\left(1-\sin^2x\right)\left(1+\tan^2x\right) dapat disederhanakan  menjadi ... 

    answer choices

     1+sin2x1+\sin^2x  

     sin2 xcos2 x\sin^2\ x-\cos^2\ x  

     1+cos2x1+\cos^2x  

     11  

     sin2x\sin^2x  

  • Question 7
    300 seconds
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    Q.

     sin2x+sin2xtan2x\sin^2x+\sin^2x\cdot\tan^2x  bentuk sederhananya adalah...

    answer choices

     22  

    1

     tan2x\tan^2x  

     cotan2x\operatorname{cotan}^2x  

     sinx cosx\sin x\ \cos x  

  • Question 8
    60 seconds
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    Q.

    Bentuk tanθ\tan\theta  adalah ...

    answer choices

     cosθsinθ\frac{\cos\theta}{\sin\theta}  

     sinθcosθ\frac{\sin\theta}{\cos\theta}  

     1cosθ\frac{1}{\cos\theta}  

     1sinθ\frac{1}{\sin\theta}  

     1tanθ\frac{1}{\tan\theta}  

  • Question 9
    60 seconds
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    Q.

     sec2αtan2αsin2α+cos2α\frac{\sec^2\alpha-\tan^2\alpha}{\sin^2\alpha+\cos^2\alpha}  adalah ...

    answer choices

     1-1  

     11  

     tan x\tan\ x  

     cotan x\operatorname{cotan}\ x  

     secx\sec x  

  • Question 10
    60 seconds
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    Q.

     sinθcosecθ\frac{\sin\theta}{\operatorname{cosec}\theta}  adalah ...

    answer choices

     sin2θ\sin^2\theta  

     cos2θ\cos^2\theta  

     tan2θ\tan^2\theta  

     cosec2θ\operatorname{cosec}^2\theta  

     sec2θ\sec^2\theta  

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