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- 1. Multiple Choice
What is specific latent heat (L)?
The amount of energy required to change the state of 1kg of the substance with a little temperature change.
Is the energy transferred to 1kg of substance to raise its temperature by 1oC.
The amount of energy required to change the state of 1kg of the substance with no temperature change.
The energy hiding in the substance.
- 2. Multiple Choice
This is the formula for latent heat of fusion:
- 3. Multiple Choice
Choose the correct symbol and unit for specific latent heat!
L(kg/J
L(J/kg)
Q(J/kgoC)
W=P/T
- 4. Multiple Choice
What is the formula to find the amount of heat energy (Q) necessary when there's a phase change
Q= (h)(ΔT)
Q=(m)(L)
Q=(m)(c)(ΔT)
Q=(k)(A)(dT)
- 5. Multiple Choice
How do you calculate latent heat of vaporization?
Lv = Q/m
c = Q/(mΔƟ)
Q = mcΔƟ
Q = mLv
- 6. Multiple Choice
What is the equation to measure change in Thermal Energy?
Q=mC∆T
Q=mC
Q= ∆mCT
C=Q/m∆T
- 7. Multiple Choice
The temperature is increasing in a glass of water. Describe the effect on its particles:
Particles would slow down
They would stop moving
They would speed up
There would be no effect
- 8. Multiple Choice
How do we calculate the heat energy released when 100 g of steam condenses.? Latent heat of vaporization = 2 300 000 J/Kg
100g x 2 300 000J/kg
10kg x 2 300 000J/kg
0.1kg x 2 300 000J/kg
0.1kg x 2 300 000J/kg x 100oC
- 9. Multiple Choice
How much heat is needed to change 8 grams of ice at 0 ºC to 12 grams of water at 0ºC? L(heat of fusion) = 334 kJ/kg; C (specific heat capacity of water) = 4186 J/kgoC
Q = 8g x 4186 J/kg0C
Q = 8g x 334kJ/kg
Q = 8000kg x 334kJ/kg
Q = 0.008 kg x 334kJ/kg
- 10. Multiple Choice
How much heat must be lost to change 110 grams of water at 0 ºC to 110 grams of ice at 0ºC? Heat of fusion = 334 kJ/kg; Specific heat of water = 4186 J/kgoC
Q = 110 x 4186
Q = 110000 x 4186
Q = 0.110 x 334
Q = 110 x 334
- 11. Multiple Choice
What is the formula to calculate heat energy required to raise the temperature of any substance?
Q = m C ∆T
Q = m Cp
Q = ½ m v
m = Q Cp
- 12. Multiple Choice
If the specific heat of water is 4,186 J/kg°C, how much heat is required to increase the temperature of 2 kg of water from 20 °C to 40 °C?
Q = 2kg x 4186J/kgoC
Q = 2kg x 4186oC x 40J/kgoC
Q = 2kg x 4186J/kgoC x 20oC
Q = 0.0012g x 4186J/kgoC x 20oC
- 13. Multiple ChoiceUsing the heat equation, what would the formula look like if we were solving for change in temperature?Q m = ∆T CpQ / (m Cp) = ∆TQ m / Cp = ∆Tm c Q = ∆T
- 14. Multiple Choice
What unit do you use to measure Thermal Energy(Q)?
J/Kg ºC
Kg
ºC
J
- 15. Multiple Choice
Describe the temperature during melting:
the temperature slowly rising
the temperature is not changing stays at 0oC
the temperature is decreasing
melting generates heat
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