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14 questions
At point P, _______.
the force applied to the spring is equal to its elongation
Hooke's Law ceases to be valid
the spring is can be stretched but still springs back into shape reversibly
the spring constant increases
How is this graph used to find the spring constant?
area under the curve
read the y-axis
read the x-axis
slope
Which quantity can be determined from this graph?
the net force is 4N
the spring is 0.4m long
the stored potential energy in this spring is 1.6 J
the spring constant is 10 N/m
When comparing spring A to B,
both experience the same maximum force
both experience the same elongation
both store the same amount of elastic potential energy
both have identical spring constants
When comparing spring A to B,
A has a larger spring constant than B so A is a stiffer spring
B has a larger spring constant than A so A is a stiffer spring
A has a larger spring constant than B so B is a stiffer spring
B has a larger spring constant than A so B is a stiffer spring
When the string is cut, the spring will
convert kinetic energy to spring potential energy
convert chemical potential energy to kinetic energy
convert spring potential energy to kinetic energy
depends on whether there are inclined planes nearby
As the person pulls the block from O to B, the spring potential energy of the system
increases
decreases
remains the same
Why are points B and C equidistant around the equilibrium length of the spring?
because there is more kinetic energy at the equilibrium position
because there is the same amount of spring potential energy at B as C
because the spring has a positive spring constant when stretched and negative when compressed
because the block has maximum kinetic energy at point B and C
At what point is the kinetic energy of the system maximized?
B
O
C
before the hand did work
As the hand pulls down on the mass, the spring constant _______, assuming that it doesn't pass the elastic limit of the spring.
increases
decreases
remains roughly constant
needs more information
A spring with constant k is elongated from equilibrium by a distance x. If it were stretched to a distance of 2x, how would the spring constant change?
k would decrease by 1/2
k would increase to twice as large
k would remain the same
A spring with constant k is elongated from equilibrium by a distance x. If it were stretched to a distance of 2x, how would the spring force change?
F would decrease by 1/2
F would increase to twice as large
F would remain the same
A spring with constant k is elongated from equilibrium by a distance x. If it were stretched to a distance of 2x, how would the energy stored in the spring change?
PEs would decrease by 1/4
PEs would decrease by half
PEs would remain the same
PEs would increase by 2
PEs would increase by 4
Which would have a increase the stored energy in a spring by the largest factor?
doubling the spring constant
doubling the elongation
doubling the equilibrium length
all of the above result in equal increases
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