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10 questions
limx→∞ 2x+6x−6=...\lim_{x\rightarrow\infty}\ \frac{2x+6}{x-6}=...x→∞lim x−62x+6=...
1
2
3
4
∞\infty∞
limx→∞ 1−2x+2x3x3+x+1= ...\lim_{x\rightarrow\infty}\ \frac{1-2x+2x^3}{x^3+x+1}=\ ...x→∞lim x3+x+11−2x+2x3= ...
- 4
- 2
limx→∞ 3x2+x+2x3+2x2+1 = ...\lim_{x\rightarrow\infty}\ \frac{3x^2+x+2}{x^3+2x^2+1}\ =\ ...x→∞lim x3+2x2+13x2+x+2 = ...
0
1,5
limx→∞ 6x3+x2+22x3+x+1 = ...\lim_{x\rightarrow\infty}\ \frac{6x^3+x^2+2}{2x^3+x+1}\ =\ \ ...x→∞lim 2x3+x+16x3+x2+2 = ...
limx→∞ (3xx−2 − 2x−2)\lim_{x\rightarrow\infty}\ \left(\frac{3x}{x-2}\ -\ \frac{2}{x-2}\right)x→∞lim (x−23x − x−22)
limx→∞ (2x3+5x+3x3−5x−1)3 = ...\lim_{x\rightarrow\infty}\ \left(\frac{2x^3+5x+3}{x^3-5x-1}\right)^3\ =\ ...x→∞lim (x3−5x−12x3+5x+3)3 = ...
8
27
64
limx→y x4 +3x2+2x3+x2+1 = ...\lim_{x\rightarrow y}\ \frac{x^4\ +3x^2+2}{x^3+x^2+1}\ =\ ...x→ylim x3+x2+1x4 +3x2+2 = ...
limx→∞ 2x + 1x−1 = ...\lim_{x\rightarrow\infty}\ \frac{2x\ +\ 1}{x-1}\ =\ ...x→∞lim x−12x + 1 = ...
- ∞\infty∞
limx→∞ x2x+1= ...\lim_{x\rightarrow\infty}\ \frac{x^2}{x+1}=\ ...x→∞lim x+1x2= ...
− ∞-\ \infty− ∞
− 2-\ 2− 2
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