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10 questions
A cannonball is fired at a 45.0° angle and an initial velocity of 625 f/s. Assume no air resistance. Find the horizontal coordinate of the cannonball after 2 seconds.
1250 f/s
883.9 f/s
441.9 f/s
328.3 f/s
The height of an object can be modeled by the formula h(t) = -16t2 + 70t + 95, where h(t) is in feet after t seconds.
What is the height of the object after 5 seconds?
95 feet
45 feet
70 feet
171.56 feet
An NFL punter at the 20 yard line kicks a football downfield with an initial velocity of 75 ft/sec at an angle of 660. The ball leaves his foot at a height of 3 feet.
Model the scenario using parametric equations.
x = (20cos(660))t; y=-16t2 + (20sin(660)t + 75
x = (20cos(660))t; y=-16t2 + (20sin(660)t + 3
x = (75cos(660))t; y=-16t2 + (75sin(660)t + 20
x = (75cos(660))t; y=-16t2 + (75sin(660)t + 3
What is the initial height of the parabola?
h = 0.563
h = 10.063
h = 5
h = 1.356
How long does it take the parabola to reach the ground?
t = 0.563
t = 10.063
t = 5
t = 1.356
A stone is thrown off a bridge 70 feet above the water at an angle of elevations of 48 ° with an initial velocity of 40 feet per second. Find the maximum height of the stone.
83.81 feet
84.57 feet
85.02 feet
86.38 feet
A stone is thrown off a bridge 70 feet above the water at an angle of elevations of 48° with an initial velocity of 40 feet per second. Find the horizontal distance the stone traveled at the time it reaches the surface of the water (h = 0)
83.04 fett
83.92 feet
84.56 feet
86.18 feet
A stone is thrown off a bridge 70 feet above the water at an angle of elevations of 48 ° with an initial velocity of 40 feet per second. Find the height of the stone at the time it reaches a horizontal distance of 80 feet.
14.76 feet
15.12 feet
15.84 feet
16.22 feet
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