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20 questions
What are the coordinates of the center and the radius of the circle with equation (x - 4)2 + (y - 3)2 = 25 ?
Center (4, 3)
Radius = 5 units
Center (4, 3)
Radius = 25 units
Center (-4, -3)
Radius = 25 units
Center (-4, -3)
Radius = 5 units
Write the standard equation of the circle with the given center and radius; center (0, 0) and radius of 3.
x2 + y2 = 4
x2 + y2 = 81
x2 + y2 = 9
x2 + y2 = 3
What is the radius of the circle with this equation of (x - 5)² + (y + 7)² = 8?
4
8
4√2
2√2
What is the radius of the circle given by the equation (x - 7)2 + (y + 3)2 = 25?
3
5
10
25
A circle has the equation x2 + y2 - 12x + 8y + 3 = 0. Write the equation in standard form.
(x - 6)2 + (y + 4)2 = 49
(x + 4)2 + (y - 6)2 = 49
(x - 6)2 + (y + 4)2 = 55
x2 + y2 = 55
What is the radius of the circle with this equation x² + y² - 10x + 8y - 23 = 0?
4
2
8
23
Change the following equation to standard form
x2 + y2 - 4x + 12y - 8 = 0
(x + 2)2 + (y - 6)2 = 48
(x - 2)2 + (y + 6)2 = 48
(x - 6)2 + (y - 2)2 = 48
(x + 2)2 + (y - 6)2 = 48
What is the center for the circle with this equation x² + y² + 4x + 6y - 36 = 0?
(-2, 5)
(2, 7)
(-2, -7)
(-2, -3)
The equation of a circle is x2 + y2 + 6x - 12y + 20 = 0. Write the equation in standard form.
(x - 3)2 + (y + 6)2 = 25
(x + 3)2 + (y - 6)2 = 25
(x - 3)2 + (y + 6)2 = 45
(x + 3)2 + (y - 6)2 = 5
Determine the equation of the circle in standard form:
x² + y² + 4x + 6y - 36 = 0
(x + 2)2 + (y + 3)2 = 49
(x + 2)2 + (y + 3)2 = 13
(x - 2)2 + (y - 3)2 = 49
(x - 2)2 + (y - 3)2 = 13
A circle has the equation x2 + y2 + 10x - 4y + 20 = 0. Write it in standard form.
(x - 5)2 + (y + 2)2 = 9
(x + 5)2 + (y - 2)2 = 3
(x + 5)2 + (y - 2)2 = 9
(x - 5)2 + (y + 2)2 = 3
A circle has the equation x2 + y2 - 8x + 6y - 11 = 0. Write it in standard form.
(x - 4)2 + (y + 3)2 = 36
(x - 4)2 + (y + 3)2 = 6
(x + 4)2 + (y - 3)2 = 36
(x + 4)2 + (y - 3)2 = 6
A circle has the equation x2 + y2 + 8x - 20 = 0. Write the equation in standard form.
(x + 4)2 + y2 = 6
(x + 4)2 + y2 = 36
(x - 4)2 + y2 = 6
(x - 4)2 + y2 = 36
A circle has the equation x2 + y2 - 6y - 5 = 0. Write the equation in standard form.
x2 + (y + 3)2 = 7
x2 + (y - 3)2 = 7
x2 + (y + 3)2 = 14
x2 + (y - 3)2 = 14
Find the center and radius of the circle: x2 + y2 + 14x - 2y = -1.
center = (-7, 2) radius = 3
center = (-7, 1) radius = 7
center = (-4, 1) radius = 7
center = (-4, 2) radius = 3
Write the equation of the circle with center C( -5 , 8 ) and radius = 7
( x - 5 )2 + ( y + 8 )2 = 14
( x - 5 )2 + ( y - 8 )2 = 49
( x - 5 )2 + ( y + 8 )2 = 49
( x + 5 )2 + ( y - 8 )2 = 49
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