Solving Linear and Quadratic Systems
9 months ago
mfranc
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10 QuestionsShow answers
  • Question 1
    900 seconds
    Q.

    Which of the following represents the first step in solving:

    y = x2 + 3x - 5

    y = x + 3

    answer choices

    x2 - 3x + 5 = x - 3

    x2 + 3x - 5 = x + 3

    x2 + 3x - 5 + x + 3 = 0

    x2 + 3x - 5 = 0

  • Question 2
    900 seconds
    Q. What are the solutions to the system:
    y = x2 + 3x - 5
    y = x + 3
    answer choices
    (-4, 2) and (-1, 5)
    (-4, -1) and (2, 5)
    (2, -1 and (-4, 5)
    (-4, 1) and (2, -1)
  • Question 3
    900 seconds
    Q. Find the solution:
    y = x2 - 4x + 6
    y = x + 2
    answer choices
    (3, 1) and (6, 4)
    (-1, 1) and (4, 2)
    (1, 3) and (4, 6)
    (1, 4) and (3, 6)
  • Question 4
    300 seconds
    Q.
    answer choices
    A
    B
    C
    D
  • Question 5
    300 seconds
    Q. Determine the solution to the given linear-quadratic function.
    answer choices
    (0, 0)
    (3, 0)
    (2, -3)
    (-3, 2)
  • Question 6
    300 seconds
    Q. Two equations were graphed on the set of axes below.  Which point is a solution to the system of equations ?
    answer choices
    (0,3)
    (5,0)
    (2,-3)
    (8,9)
  • Question 7
    900 seconds
    Q. Solve the system of linear and quadratic equations using substitution:
    y = 5
    y = 2x2 - 16x + 29
    answer choices
    (6, 5) and (2, 5)
    (2, 6)
    (6, 2)
    (5, 6) and (5, 2)
  • Question 8
    900 seconds
    Q. What are the factor of x2 + 2x - 8?
    answer choices
    (x + 4)(x + 2)
    (x - 4)(x - 2)
    (x - 4)(x + 2)
    (x + 4)(x - 2)
  • Question 9
    300 seconds
    Q. Given the system of equations:
    y = x2 + 3x - 5
    y = x + 3
    When x = -4, what is the value of y?
    answer choices
    -1
    1
    7
    -33
  • Question 10
    900 seconds
    Q. Find the solution.
    answer choices
    (0,7) and (0,-3)
    (2,6) and (7,4)
    (3,0) and (7,4)
    (-1,5) and (-3,9)
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