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- 1. Multiple Choice
Homer sells tickets for admission to your school play and collects a total of $104. Admission prices are $6 for adults and $4 for children. He sold 21 tickets total. Write a system to represent this situation assuming "a" represents # of adult tickets and "c" represents # of children's tickets.
a + c = 21
6a + 4c = 104
a + c = 104
6a + 4c = 21
a + c = 21
6c + 4a = 104
a + c = 104
6c + 4a = 21
- 2. Multiple ChoiceHomer sells tickets for admission to your school play and collects a total of $104. Admission prices are $6 for adults and $4 for children. He sold 21 tickets total. Solve the system:
x + y = 21
6x + 4y = 104(10, 11)(12, 9)(11, 10)(9, 12) - 3. Multiple Choice
David is running a concession stand at a soccer game. He sells nachos and sodas. Nachos cost $1.50 each and sodas cost $0.50 each. At the end of the game, David made a total of $78.50 and sold a total of 87 nachos and sodas combined. Which system of equations represents this situation? *
x + y = 78.5
x + y = 87
1.5x + 0.5y = 78.5
1.5x + 0.5y = 87
x + y = 78.5
1.5x + 0.5y = 87
1.5x + 0.5y = 78.5
x + y = 87
- 4. Multiple ChoiceYour family goes to a restaurant for dinner. There are 6 people in your family. Some order the chicken dinner for $14.80, and some order steak for $17. If the total bill was $91, which system best represents the situation?x + y = 6
14.80x + 17y = 91x + y = 91
14.80x + 17y = 6x + y = 6
14.80y + 17x = 91x + y = 91
14.80x+ 17y = 6 - 5. Multiple ChoiceCaitlin won a bag full of money! She has 49 bills in all. She counts $1430. There are twenty dollar bills and fifty dollar bills. How many of each bill does Caitlin have? Which system best represents the situation?x + y = 1430
20x + 50y = 49x + y = 49
10x + 5y = 1430x + y = 49
20x + 50y = 1430x + y = 49
x + y = 1430 - 6. Multiple Choice
Flagship Cinemas sells movie tickets that are $4 for matinees and $7 for regular. One night, the theater sells 578 tickets and collects $3365 in total ticket sales.
Which system best represents the situation?
4x + 7y = 3365
x + y = 578
4x + 7y = 578
x + y = 3365
4y + 7x = 578
x + y = 3365
4y + 7x = 578
x + y = 578
- 7. Multiple ChoiceYour family goes to a southern style restaurant for dinner. There are 6 total people in your family. Some order chicken for $14 and the rest order steak for $17. The total bill is $99. Write a system that could represent this situation.c + s = 6
14c + 17s = 99c + s = 99
14c + 17s = 6c + s = 6
17c + 14s = 99c + s = 99
17c + 14s = 6 - 8. Multiple Choice
A sporting goods store sells left haded (x) and right handed (y) gloves. In one month, 12 gloves were sold for a total of $561. Right handed gloves cost $45 each and left handed gloves cost $52. Which system could be solved to determine the number of each type of glove sold?
x + y = 561
45x+52y=12
x + y = 12
52x+45y=561
x + y = 12
45x+52y=561
x + y = 561
52x+45y=12
- 9. Multiple ChoiceSolve for x and y.
y = 2/3x - 2
y = -x + 3(0,3)(0,-3)(3,0)(-3,0) - 10. Multiple ChoiceTickets to a movie cost $7.25 for adults and $5.50 for students. A group of friends purchased 8 tickets for $52.75. Which system could be solved to determine the number of adult tickets (a) and student tickets (s) purchased?a+s=52.75
5.5a+7.25s=8a + s = 8
5.5a+7.25s=52.75a + s = 52.75
7.25a+5.5s=8a + s = 8
7.25a+5.5s=52.75 - 11. Multiple ChoiceJack's BBQ sold 120 pounds of pork shoulder and brisket for an event. They grossed $1109.55 from the sale. The going rate for pork shoulder is $8.29 per pound and brisket is $9.82 per pound. How much brisket and pork shoulder did Jack's BBQ sell?65 pounds of pork shoulder
55 pounds of brisket75 pounds of pork shoulder
45 pounds of brisket60 pounds of bothI thought Jack's BBQ was a vegetarian restaurant. - Answer choicesTagsAnswer choicesTags