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- 1. Multiple ChoiceA force of 30 N stretches a very light ideal spring 0.73 m from equilibrium. What is the force constant (spring constant) of the spring?41 N/m22 N/m34 N/m46 N/m
- 2. Multiple ChoiceA pair of trapeze performers at the circus is swinging from ropes attached to a large elevated platform. Suppose that the performers can be treated as a simple pendulum with a length of 16 m. Determine the period for one complete back and forth cycle.2 sec12 sec8 sec10 sec
- 3. Multiple ChoiceA pendulum is 0.75 meters long and has a period of 4.17 seconds. The Pendulum is on an unknown planet. What is the gravity of the Unknown Planet?9.83.41.7Greater than 9.8
- 4. Multiple ChoiceIf the length of a simple pendulum is doubled, its period will:halveincrease by a factor of sqrt(2)decrease by a factor of sqrt(2)double
- 5. Multiple Choice
From the graph ,the spring constant is.
4.5 m
15 N
20 N/m
200 N/m
- 6. Multiple ChoiceWhat is the equation for frequency?f = t/nf = 1/Tf = 2 T
- 7. Multiple ChoiceA mass-spring system can oscillate with simple harmonic motion because a compressed or stretched spring has which kind of energy?kineticmechanicalgravitational potentialelastic potential
- 8. Multiple ChoiceFor a system in simple harmonic motion, which of the following is the number of cycles or vibrations per unit of time?amplitudeperiodfrequencyrevolution
- 9. Multiple ChoiceWhat is the period on Earth of a pendulum with a length of 2.4 m?3.1 sec1.9 sec9.3 sec5.1 sec
- 10. Multiple Choice
Based on your findings, which equation could best describe the pendulum’s period?
A
B
C
D
- 11. Multiple ChoiceA simple harmonic oscillator takes 4.8 s to undergo five complete vibrations. What is the frequency of 1cycle?1.04 s4.8 s1/4.8 s
- 12. Multiple ChoiceA simple harmonic oscillator takes 4.8 s to undergo five complete vibrations. What is the period (T) of 1 cycle?4.8 s.96 s9.8 s
- 13. Multiple ChoiceWhat is the frequency of a pendulum that has a period of 10 s?10 Hz1/1000 Hz.1 Hz
- 14. Multiple ChoiceThe period of a pendulum may be decreased byIncreasing the mass of the bobmoving the equilibrium pointdecreasing the mass of the bobshortening the length of pendulum
- 15. Multiple Choice
The velocity of a spring-block system vibrating along the y-axis changes with time according to the equation: 𝑣(𝑡) = 2𝜋 cos(𝜋𝑡 + 𝜋). All quantities in the equation are expressed in S.I units. Consider that the object is initially at the equilibrium position. What is the amplitude of the motion of the object in meter?
2/𝜋
2
2𝜋
𝜋/2
- 16. Multiple Choice
A block of mass 2.0 kg is attached to a spring. What is the spring constant if the block’s acceleration is 13 m/s2 when it is 0.75 m away from the equilibrium position ?
35 N/m
22 N/m
12 N/m
8 N/m
- 17. Multiple Choice
The velocity of a spring-block system vibrating along the y-axis changes with time according to the equation: 𝑣(𝑡) = 2𝜋 cos(𝜋𝑡 + 𝜋). All quantities in the equation are expressed in S.I units. Consider that the object is initially at the equilibrium position. What is the maximum acceleration of the object?
𝜋
2𝜋
2𝜋2
𝜋/2
- 18. Multiple Choice
The velocity of a spring-block system vibrating along the y-axis changes with time according to the equation: 𝑣(𝑡) = 2𝜋 cos(𝜋𝑡 + 𝜋). All quantities in the equation are expressed in S.I units. Consider that the object is initially at the equilibrium position. What is the value of the velocity (in m/s) at the instant when the acceleration is zero?
2𝜋
2𝜋2
𝜋
𝜋/2
- 19. Multiple Choice
The maximum velocity occurs where the ____.
potential energy is a maximum
kinetic energy is a minimum
displacement from equilibrium is equal to
the amplitude of 0.4 𝑚
displacement from equilibrium is equal to
zero
- 20. Multiple Choice
An object of mass 𝑚 is attached to a horizontal spring, stretched to a displacement 𝐴 from equilibrium and released, undergoing harmonic oscillations on a frictionless surface with period 𝑇 . The experiment is then repeated with a mass of 4𝑚. What’s the new period of oscillation?
2T
T
4T
T√2
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