Exponential Growth and Decay
2 years ago
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16 QuestionsShow answers
  • Question 1
    300 seconds
    Q. A population of 1500 deer decreases by 1.5% per year. At the end of 10 years, there will be approximately 1290 deer in the population. Which function can be used to determine the number of deer, y, in this population at the end of t years?
    answer choices
    y = 1500(1 - 0.015)t
    y = 1500(0.015)t
    y = 1500(1 + 0.015)t
    y = 1500(1.5)t
  • Question 2
    300 seconds
    Q. There were 417 cell phones sold at an electronics store in January. Since then, cell phone sales at this store have increased at a rate of 3.75% per month. At this rate of growth, which function can be used to determine the monthly cell phone sales x months after January?
    answer choices
    f(x) = 417(3.75)x
    f(x) = 417(0.0375)x
    f(x) = 417(1.0375)x
    f(x) = 417(1.375)x
  • Question 3
    300 seconds
    Q.
    answer choices
    g(x) = 10x
    f(x) = 0.1x
    g(x) = 10x
    g(x) = 10(2)x
  • Question 4
    300 seconds
    Q.
    answer choices
    The graph represents an exponential growth situation.
    Eventually, the car will be worth exactly $0.
    The starting value of the car was $12,000.
    The range for the situation is y ≥ 0.
  • Question 5
    300 seconds
    Q.
    answer choices
    x > 0
    y > 0
    -∞ < x < ∞
    -∞ < y < ∞
  • Question 6
    300 seconds
    Q. An antibiotic is introduced into a colony of 12,000 bacteria during a laboratory experiment. The colony is decreasing by 14.9% per minute. Which function can be used to model the number of bacteria in the colony after x minutes?
    answer choices
    f(x) = 12000(1 + 14.9)x
    f(x) = 12000(1 - 14.9)x
    f(x) = 12000(1 + 0.149)x
    f(x) = 12000(1 - 0.149)x
  • Question 7
    300 seconds
    Q. Some banks charge a fee for a savings account that is left inactive for an extended period of time. The equation y = 5000(0.98)x represents the amount remaining, y, of one account that was left inactive for a period of x years. What does the number 5000 represent in this situation?
    answer choices
    A fee charged for an inactive account
    The percent of money in the account after x years
    The amount of money in the account initially
    The amount of money in the account after x years
  • Question 8
    300 seconds
    Q.
    answer choices
    f(x) = 35(0.95)x
    f(x) = 36(0.05)x
    f(x) = 35(1.05)x
    f(x) = 36(1.5)x
  • Question 9
    300 seconds
    Q.
    answer choices
    This function is an example of exponential growth.
    This function has a y-intercept at (0, 200).
    The growth factor for this function is 4.
    The range for this function is y > 0.
  • Question 10
    300 seconds
    Q. A child asks her dad for an allowance that starts with a penny and then doubles every day for a month. Which function can be used to model the amount of money, A, the child will receive each day, x?
    answer choices
    A(x) = 2(0.01)x
    A(x) = 0.01(2)x
    A(x) = 0.01(1 - 2)x
    A(x) = 2(1.01)x
  • Question 11
    300 seconds
    Q.
    answer choices
    F
    G
    H
    J
  • Question 12
    300 seconds
    Q.
    answer choices
    The graph of this situation represents exponential decay.
    The range of this function is y > 0.
    There is a horizontal asymptote at y = 0 for this situation.
    The y-intercept is (0, 230).
  • Question 13
    300 seconds
    Q.
    answer choices
    -∞ < y < ∞
    y > 0
    -∞ < x < ∞
    x > 0
  • Question 14
    300 seconds
    Q.
    answer choices
    The number of players decreases by 30% each round.
    The range for the function is 1 < y < 5.
    The domain for the function is 5 < x < 65.
    The situation represented is exponential decay.
  • Question 15
    300 seconds
    Q.
    answer choices
    F
    G
    H
    J
  • Question 16
    300 seconds
    Q. The function to find the value of a car after t years is given by v(t) = 24,000(.75)t Which of the following statements is not true?
    answer choices
    The starting value of the car was $24,000.
    The y-values of the graph increase as the x-values increase.
    The value of b indicates this is an exponential decay situation.
    The horizontal asymptote is y = 0, which means the car will never have a value of $0.
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