Lesson Proportions
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• Slide 1
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Proportions

Text • Slide 2
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Proportions

• A proportion is an equation stating that two ratios (fractions) are equal.

• If a proportion contains a variable, use cross multiplication and single-step algebra to find the missing value.

• Slide 3
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• Question 4
120 seconds
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Q.

Solve for x.
$\frac{2}{5}=\frac{x}{65}$

x = 16

x =  $\frac{1}{26}$

x = 28

x = 26

• Question 5
120 seconds
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Q.

Solve the proportion:

$\frac{2}{7}=\frac{c}{28}$

4

14

8

10

• Question 6
120 seconds
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Q.

Solve for the variable k.

$\frac{k}{6}=\frac{15}{18}$

k = 5

k = 60

k =  $\frac{10}{3}$

k = 90

• Question 7
120 seconds
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Q.

Solve the proportion:

$\frac{8}{x}=\frac{12}{30}$

x = 15

x =  $\frac{1}{11}$

x = 11

x = 20

• Slide 8
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• Question 9
180 seconds
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Q.

Solve the proportion.
$\frac{a-6}{5}=\frac{7}{12}$

$\frac{29}{12}$

$\frac{107}{12}$

$\frac{41}{12}$

13

• Question 10
180 seconds
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Q.

Solve for x.

$\frac{x+3}{4}=\frac{7}{8}$

$\frac{1}{2}$

11

$\frac{25}{8}$

$\frac{53}{4}$

• Question 11
180 seconds
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Q.

Solve the proportion:

$\frac{8}{9}=\frac{w-2}{6}$

$\frac{10}{3}$

$\frac{46}{9}$

$\frac{50}{9}$

$\frac{22}{3}$

• Question 12
180 seconds
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Q.

Solve the equation for x:

$\frac{40}{x+1}=\frac{15}{6}$

17

15

16

14

• Slide 13
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• Slide 14
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• Question 15
300 seconds
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Q.

Solve for x.

$\frac{x-5}{7}=\frac{x-8}{11}$

$x\ =\ -\frac{1}{4}$

$x\ =\ -\frac{3}{4}$

$x\ =\ \frac{1}{3}$

$x\ =\ \frac{3}{4}$

• Question 16
300 seconds
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Q.

Solve the proportion:

$\frac{8}{b+10}=\frac{4}{2b-7}$

b = 8

b =  $\frac{4}{3}$

b =  $\frac{17}{12}$

b =  $\frac{1}{8}$

• Question 17
300 seconds
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Q.

Solve for k:

$\frac{k+5}{10}=\frac{k-12}{9}$

165

$\frac{1}{17}$

17

$\frac{1}{165}$

• Question 18
300 seconds
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Q.

Solve the proportion:

$\frac{8}{x-10}=\frac{4}{x+9}$

-9

9

-28

4

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